MP Board Class 12 Chemistry Ch4: d and f Block Elements
Chapter 4: The d- and f-Block Elements (d एवं f-ब्लॉक तत्व) is one of the most scoring chapters of MP Board Class 12 Chemistry. You study transition (d-block) elements, their electronic configuration, general properties, important compounds like K2Cr2O7 and KMnO4, and f-block elements — lanthanoids and actinoids. These complete notes with tables, formulas and board questions are prepared for the MP Board 2027 exam. Practice free chapter tests and previous year papers at mpboard.ai.
📑 Table of Contents
- 1. Introduction to d-Block (Transition) Elements
- 2. Electronic Configuration of d-Block Elements
- 3. General Properties of Transition Elements
- 4. Oxidation States, Colour, Magnetic and Catalytic Properties
- 5. Important Compounds: K₂Cr₂O₇ and KMnO₄
- 6. f-Block Elements: Lanthanoids and Actinoids
- 7. Lanthanoid Contraction and Comparison
- 8. Key Points Quick Revision Table
- 9. Important Points for MP Board Exam
- 10. Important Questions for MP Board 2027
- 11. Frequently Asked Questions (FAQs)
🧪 1. Introduction to d-Block (Transition) Elements
The d-block elements are those in which the last electron enters the d-orbital of the penultimate (n–1) shell. They occupy groups 3 to 12, between the s-block and p-block elements, and form a bridge between the electropositive s-block metals and the less electropositive p-block elements — hence they are called transition elements.
By IUPAC definition, a transition element has a partially filled d-orbital in the ground state or in any common oxidation state. Therefore Zn, Cd and Hg are not transition elements — they have a completely filled (n–1)d10 configuration in the ground state and in their common +2 oxidation state.
⚡ MP Board Tip: “Why is Zn not a transition element?” is a repeated 1-mark question. Answer: Zn has completely filled 3d10 configuration in ground state and in +2 oxidation state.
⚛️ 2. Electronic Configuration of d-Block Elements
The general electronic configuration is (n–1)d1–10 ns1–2. In the 3d series the 4s orbital fills before 3d because it has lower energy. Two elements show anomalous configurations due to the extra stability of half-filled and fully-filled d orbitals:
- Chromium (Cr): [Ar] 3d5 4s1 (not 3d4 4s2)
- Copper (Cu): [Ar] 3d10 4s1 (not 3d9 4s2)
📘 Key Point: In the 6th period, the 4f orbitals (lanthanoids) fill before 5d, so the 5d series begins at Hf (72) after lanthanum. This is why the 6th period contains 32 elements.
📊 3. General Properties of Transition Elements
Transition elements differ from s-block and p-block elements in many properties. The table below summarises the general properties with reasons — exactly the pattern MP Board asks in long-answer questions:
⚡ MP Board Tip: For alloy/interstitial compound questions, write similar atomic radii (alloys) and presence of voids (interstitial compounds) as the reasons.
🎨 4. Oxidation States, Colour, Magnetic and Catalytic Properties
Variable Oxidation States
Because the (n–1)d and ns orbitals have very close energies, transition elements show variable oxidation states. For example, Mn shows +2 to +7 and Cr shows +2 to +6. The highest oxidation state equals the group number up to group 7 (Mn +7); after group 8 it becomes less common.
Colour of Transition Metal Ions
Most transition metal ions are coloured due to d–d transitions: visible light excites an electron from a lower d-orbital to a higher d-orbital, absorbing a particular wavelength, and the transmitted light gives the colour. Ions with no unpaired d-electrons, such as Zn2+ (d10) and Sc3+ (d0), are colourless.
Magnetic and Catalytic Properties
Substances with unpaired electrons are paramagnetic (attracted by a magnetic field); transition metals and ions show paramagnetism due to unpaired d-electrons. Fe, Co and Ni are ferromagnetic in the solid state and are used for permanent magnets. As catalysts, transition metals work through variable oxidation states and intermediate complex formation: V2O5 (contact process), Fe (Haber process), Ni (hydrogenation of oils) and Pt (Ostwald process).
🧪 5. Important Compounds: K₂Cr₂O₇ and KMnO₄
Potassium Dichromate (K₂Cr₂O₇)
Potassium dichromate forms orange-red crystals and is a strong oxidising agent. It is prepared from chromite ore (FeCr2O4): the ore is fused with sodium carbonate and lime in air to give Na2CrO4, which is leached with water, acidified with dilute H2SO4 to Na2Cr2O7, and then treated with KCl to crystallise out K2Cr2O7.
In acidic medium: Cr2O72– + 14H+ + 6e– → 2Cr3+ + 7H2O. Uses: volumetric analysis (dichromate titration), tanning of leather and chrome pigments.
Potassium Permanganate (KMnO₄)
Potassium permanganate forms dark violet crystals. It is prepared from pyrolusite ore (MnO2): MnO2 is fused with KOH and an oxidising agent to give green K2MnO4, which is then oxidised electrolytically to KMnO4.
KMnO4 is a powerful oxidising agent whose product depends on the medium: acidic medium → Mn2+, neutral medium → MnO2 (brown), strongly alkaline medium → MnO42– (green). Uses: disinfectant, water purification, permanganate titrations and laboratory oxidations.
⚡ MP Board Tip: In acidic medium 1 mole of KMnO₄ gains 5 electrons and 1 mole of K₂Cr₂O₇ gains 6 electrons — a favourite numerical and balancing question.
🌍 6. f-Block Elements: Lanthanoids and Actinoids
In f-block elements the last electron enters the f-orbital of the antepenultimate (n–2) shell. They are placed below the main periodic table in two series:
The common oxidation state of lanthanoids is +3; Ce (+4), Tb (+4), Eu (+2) and Yb (+2) are exceptions stabilised by empty, half-filled or fully-filled 4f orbitals. Actinoids show a wider range (+3 to +7) because 5f, 6d and 7s orbitals have close energies. All actinoids are radioactive; thorium and uranium occur in nature, the rest are synthetic.
📉 7. Lanthanoid Contraction and Comparison
Lanthanoid contraction is the steady decrease in the atomic and ionic radii of lanthanoids from La3+ (103 pm) to Lu3+ (86 pm). It occurs because the 4f electrons have a very poor shielding effect, so the increasing nuclear charge pulls the outer electrons closer.
Important consequences of lanthanoid contraction:
- Similar chemical properties — separation of lanthanoids is very difficult (done by ion-exchange and solvent extraction).
- Decrease in basicity of hydroxides from La(OH)3 to Lu(OH)3.
- Similar sizes of Zr/Hf, Nb/Ta and Mo/W in the 2nd and 3rd transition series.
📋 8. Key Points Quick Revision Table
✅ 9. Important Points for MP Board Exam
- Elements with a partially filled d-orbital in ground state or common oxidation state are transition elements.
- Zn, Cd, Hg are d-block but not transition elements (d¹⁰).
- General configuration: (n–1)d1–10 ns1–2; Cr and Cu are exceptions.
- Transition metals show variable oxidation states, coloured ions, paramagnetism, catalytic activity, and form complexes and interstitial compounds.
- K₂Cr₂O₇ (orange) is prepared from chromite; KMnO₄ (purple) from pyrolusite.
- Lanthanoid contraction = decrease in radii from La to Lu due to poor shielding of 4f electrons.
- Actinoids are all radioactive and show more variable oxidation states (+3 to +7).
- In acidic medium KMnO₄ gains 5e⁻ and K₂Cr₂O₇ gains 6e⁻ per molecule.
📝 10. Important Questions for MP Board 2027
✏️ Very Short Answer (1 Mark)
- What are transition elements?
- Why is Zn not regarded as a transition element?
- What is lanthanoid contraction?
- What is the oxidation state of Mn in KMnO₄?
- Name the ore from which potassium dichromate is prepared.
- Write the electronic configuration of Cr and Cu.
📝 Short Answer (2–3 Marks)
- Why do transition elements show variable oxidation states?
- Why are transition metal ions coloured? Explain with examples.
- Why are transition metals and their compounds good catalysts?
- What are interstitial compounds? State any two properties.
- How is potassium permanganate prepared from pyrolusite ore?
- Why do transition elements form complexes?
- What are the consequences of lanthanoid contraction?
📚 Long Answer (5–6 Marks)
- Describe the general characteristics of d-block (transition) elements.
- Compare lanthanoids and actinoids on the basis of electronic configuration, oxidation states and chemical behaviour.
- Explain the preparation, properties and uses of potassium permanganate (KMnO₄).
- Explain the preparation, properties and uses of potassium dichromate (K₂Cr₂O₇).
- Discuss the magnetic and catalytic properties of transition elements.
❓ 11. Frequently Asked Questions (FAQs)
Q1: What is the difference between d-block elements and transition elements?
d-block elements are those in which the last electron enters the d-orbital of the penultimate shell (groups 3 to 12). Transition elements are d-block elements that have partially filled d-orbitals in the ground state or in a common oxidation state. Zn, Cd and Hg are d-block elements but not transition elements because their d-orbitals are completely filled.
Q2: Why are transition metal ions coloured?
Transition metal ions are coloured because of d-d transitions. When visible light falls on the ion, an electron jumps from a lower-energy d-orbital to a higher-energy d-orbital and absorbs light of a particular wavelength. The remaining light is transmitted and gives the colour. Ions with no unpaired d-electrons, like Zn2+ (d10) and Sc3+ (d0), are colourless.
Q3: What is lanthanoid contraction and why does it occur?
Lanthanoid contraction is the steady decrease in the atomic and ionic radii of the lanthanoids from La3+ (103 pm) to Lu3+ (86 pm). It occurs because the 4f electrons have a very poor shielding effect, so the increasing nuclear charge pulls the outer electrons closer to the nucleus.
Q4: Why do transition elements form complexes?
Transition elements form complexes because they have small size, high positive charge and vacant d-orbitals of suitable energy. These vacant orbitals can accept lone pairs of electrons from ligands, forming coordinate bonds. Examples are [Cu(NH3)4]2+ and [Fe(CN)6]3-.
Q5: Why is KMnO4 a strong oxidising agent?
KMnO4 is a strong oxidising agent because manganese is present in its highest oxidation state of +7. It readily accepts electrons and gets reduced: in acidic medium to Mn2+, in neutral medium to MnO2, and in strongly alkaline medium to MnO42-. One mole of KMnO4 gains 5 electrons in acidic medium.
Q6: What are the common oxidation states of lanthanoids?
The common and most stable oxidation state of lanthanoids is +3. Some lanthanoids also show +4 (Ce, Tb) and +2 (Eu, Yb) oxidation states because of the stability of empty, half-filled or fully-filled 4f orbitals.
Q7: Why are Zn, Cd and Hg not considered transition metals?
Zn, Cd and Hg are not considered transition metals because they have a completely filled (n-1)d10 configuration in the ground state as well as in their common +2 oxidation state. Transition elements must have a partially filled d-orbital.
Q8: What is the action of K2Cr2O7 in acidic medium?
In acidic medium, potassium dichromate acts as a strong oxidising agent. The dichromate ion is reduced to Cr3+ while oxidising other substances: Cr2O72- + 14H+ + 6e- gives 2Cr3+ + 7H2O. One mole of K2Cr2O7 gains 6 electrons in acidic medium.
📘 Quick Revision Tips
- Revise the 3d series electronic configuration table — Cr and Cu exceptions are almost guaranteed in the exam.
- Learn the colour of common ions (Cu²⁺ blue, Fe³⁺ yellow, MnO₄⁻ purple) — 1-mark questions repeat every year.
- Write the preparation of K₂Cr₂O₇ and KMnO₄ as flow steps; examiners award step marks.
- Memorise the lanthanoid contraction definition plus two consequences word-for-word.
- Solve 3 years of MP Board previous year papers from mpboard.ai and mark every d/f-block question that appears.
📖 More Resources: Download MP Board Class 12 Chemistry previous year papers and practice sets from mpboard.ai. For video explanations and chapter-wise PYQ discussions, visit our Class 12 Chemistry Course.