MP Board Class 10 Science Chapter 3: Metals & Non-Metals Notes 2027 — Properties, Reactivity Series, Extraction & PYQs

Chapter 3: Metals & Non-Metals is one of the most important chapters in MP Board Class 10 Science, carrying 8–12 marks in the annual board exam. This chapter covers the physical and chemical properties of metals and non-metals, the reactivity series, extraction of metals from ores (metallurgy), and corrosion — its causes, prevention, and economic impact. Questions range from 1-mark MCQs to 5-mark detailed explanations with balanced equations. Mastering this chapter is essential for both board exams and competitive foundation exams.

⚙️ Physical Properties — Metals vs Non-Metals

Metals and non-metals have distinctly different physical properties. Understanding these differences helps in classifying elements and predicting their behaviour in chemical reactions.

📊 Comparison Table: Metals vs Non-Metals

Property Metals Non-Metals
Lustre Have a shiny appearance (metallic lustre) Dull — no metallic lustre (except iodine, graphite)
Hardness Generally hard and strong (exceptions: Na, K — soft) Generally soft (exception: diamond — hardest natural substance)
Malleability Can be hammered into thin sheets (e.g., Al foil, gold leaf) Brittle — break when hammered
Ductility Can be drawn into thin wires (e.g., Cu wire, Ag wire) Non-ductile — cannot be drawn into wires
Conductivity Good conductors of heat and electricity Poor conductors (exception: graphite conducts electricity)
Melting Point Generally high melting & boiling points (exception: Na, K, Hg) Generally low melting & boiling points (exception: diamond, graphite)
State at Room Temp Solid (except Hg — liquid at room temp) Solid or gas (exception: Br₂ — liquid)
Sonority Sonorous — produce ringing sound when struck Non-sonorous
Density Generally high density Generally low density
Tensile Strength High tensile strength (can bear load) Low tensile strength
🎯 Exam Tip: EXCEPTIONS are frequently asked in MP Board exams: (i) Mercury (Hg) is a liquid metal, (ii) Sodium (Na) and Potassium (K) are soft metals cut with a knife, (iii) Iodine (I₂) is a shiny non-metal, (iv) Graphite conducts electricity despite being a non-metal, (v) Diamond is the hardest natural substance but is a non-metal.

🔑 Key Physical Properties in Detail

1. Malleability

Malleability is the property of metals to be beaten into thin sheets. This is possible because metals have layers of atoms that can slide over one another without breaking the metallic bond.

  • Gold (Au) is the most malleable metal — can be beaten into sheets as thin as 0.0001 mm (gold leaf).
  • Aluminium (Al) is used to make aluminium foil for food packaging.
  • Silver (Ag) and Copper (Cu) are also highly malleable.

2. Ductility

Ductility is the property of metals to be drawn into thin wires. This occurs because metal atoms can rearrange along the length of the wire without breaking.

  • Gold (Au) is the most ductile metal — 1 gram of gold can be drawn into a wire up to 2 km long.
  • Copper (Cu) is widely used for electrical wiring due to its high ductility and conductivity.
  • Aluminium (Al) wires are used for power transmission lines.

3. Electrical Conductivity

Metals conduct electricity due to the presence of free (mobile) electrons in their crystal lattice. These electrons can move freely through the metal and carry electric current.

  • Silver (Ag) is the best conductor of electricity, followed by Copper (Cu) and Gold (Au).
  • Copper is most commonly used for electrical wiring due to its good conductivity and lower cost.
  • Graphite (a non-metal) can conduct electricity due to delocalised electrons in its layered structure.

4. Thermal Conductivity

Metals are good conductors of heat because free electrons transfer thermal energy rapidly through the metal. Cooking utensils are made of metals (Cu, Al, steel) because they conduct heat efficiently.

🎯 Exam Tip: Metals are lustrous, malleable, ductile, sonorous, and good conductors of heat and electricity. Non-metals generally lack all these properties. However, exceptions (especially graphite and diamond) are exam favorites!

🧪 Chemical Properties

The chemical properties of metals and non-metals determine how they react with common substances like oxygen, water, acids, and bases. These reactions are the basis for understanding the reactivity series and extraction methods.

🔥 Reaction with Oxygen (Formation of Oxides)

Metals react with oxygen to form metal oxides. Most metal oxides are basic in nature — they react with water to form bases, or with acids to form salt and water.

⚗️ Metals + Oxygen → Metal Oxide

4Na + O₂ → 2Na₂O (Sodium oxide)
2Mg + O₂ → 2MgO (Magnesium oxide)
4Al + 3O₂ → 2Al₂O₃ (Aluminium oxide)
3Fe + 2O₂ → Fe₃O₄ (Magnetite — Iron(II,III) oxide)
Cu + O₂ → 2CuO (Copper(II) oxide — black)

Different metals react with oxygen at different rates:

  • Sodium (Na) and Potassium (K) react so vigorously with oxygen that they catch fire spontaneously in air. They are stored under kerosene to prevent contact.
  • Magnesium (Mg) burns with a brilliant white flame to form MgO (magnesium oxide).
  • Aluminium (Al) forms a thin, protective layer of Al₂O₃ on its surface that prevents further corrosion.
  • Iron (Fe) burns only when heated strongly. Iron filings burn more readily.
  • Copper (Cu) does not burn but slowly forms a black coating of CuO on heating.
  • Gold (Au) and Platinum (Pt) do not react with oxygen at all — they are the least reactive.

🧪 Nature of Metal Oxides

Most metal oxides are basic — they turn red litmus blue and react with acids to form salt and water:

MgO + 2HCl → MgCl₂ + H₂O

Some metal oxides like Al₂O₃ and ZnO are amphoteric — they react with both acids and bases:

Al₂O₃ + 6HCl → 2AlCl₃ + 3H₂O (Reacts with acid)
Al₂O₃ + 2NaOH → 2NaAlO₂ + H₂O (Reacts with base → Sodium aluminate)

📘 Amphoteric Oxides

Al₂O₃ (alumina) and ZnO (zinc oxide) are amphoteric oxides — they show both acidic and basic behaviour. This is a frequently asked concept in MP Board exams.

⚗️ Non-Metals + Oxygen → Non-Metal Oxide

C + O₂ → CO₂ (Carbon dioxide)
2S + 3O₂ → 2SO₃ (Sulphur trioxide)
4P + 5O₂ → 2P₂O₅ (Phosphorus pentoxide)

Non-metal oxides are acidic in nature — they turn blue litmus red and react with bases to form salt and water:

CO₂ + 2NaOH → Na₂CO₃ + H₂O
SO₃ + 2NaOH → Na₂SO₄ + H₂O
Property Metal Oxides Non-Metal Oxides
Nature Basic (or amphoteric) Acidic
Litmus Test Turn red litmus blue Turn blue litmus red
Reaction with Acid Neutralize acids → salt + water No reaction with acids
Reaction with Base Amphoteric oxides react with bases Neutralize bases → salt + water
Example MgO, Na₂O, CaO CO₂, SO₂, SO₃, P₂O₅

💧 Reaction with Water

Metals react with water to produce metal hydroxide and hydrogen gas. The vigour of the reaction depends on the reactivity of the metal.

📋 Reactivity of Metals with Water

Metal Reaction with Water Equation
Na (Sodium) React violently with cold water — catches fire 2Na + 2H₂O → 2NaOH + H₂↑
K (Potassium) React even more violently — catches fire 2K + 2H₂O → 2KOH + H₂↑
Ca (Calcium) React less violently — bubbles of H₂ gas Ca + 2H₂O → Ca(OH)₂ + H₂↑
Mg (Magnesium) Does not react with cold water; reacts with hot water Mg + 2H₂O → Mg(OH)₂ + H₂↑
Al (Aluminium) Does not react with water due to oxide layer
Fe (Iron) Very slow reaction with steam (not liquid water) 3Fe + 4H₂O → Fe₃O₄ + 4H₂↑ (steam)
Cu, Ag, Au Do not react with water at all
🎯 Exam Tip: The reaction of metals with water is a key concept for understanding the reactivity series. Na and K react explosively, while Cu, Ag, and Au do not react at all. Watch for questions like: “Which metal reacts violently with cold water?” or “Arrange in order of reaction with water.”

Non-metals generally do not react with water. However, some non-metals like carbon react with steam: C + H₂O → CO + H₂ (water gas reaction, only at high temperatures).

🧪 Reaction with Acids

Metals react with dilute acids (HCl, H₂SO₄) to produce salt and hydrogen gas.

Metal + Dilute Acid → Salt + Hydrogen Gas
Zn + 2HCl → ZnCl₂ + H₂↑
Mg + H₂SO₄ → MgSO₄ + H₂↑
Fe + 2HCl → FeCl₂ + H₂↑
2Al + 6HCl → 2AlCl₃ + 3H₂↑

🔑 Key Observations

  • The vigour of the reaction depends on the reactivity of the metal.
  • Highly reactive metals (Na, K) react explosively — these are NOT tested with acids in the lab for safety.
  • Moderately reactive metals (Zn, Fe, Mg, Al) react readily with dilute acids.
  • Less reactive metals (Cu, Ag, Au) do NOT react with dilute acids.
  • The H₂ gas produced can be tested by the pop test — a burning matchstick near the gas produces a pop sound.
  • Nitric acid (HNO₃) is NOT used because it is a strong oxidizing agent and produces oxides of nitrogen instead of H₂.

❌ Reaction of Non-Metals with Acids

Non-metals generally do NOT react with dilute acids to produce hydrogen gas. This is because non-metals cannot displace hydrogen from acids.

🧪 Reaction with Bases

Some metals react with strong bases (alkalis like NaOH, KOH) to produce hydrogen gas. This property is limited to amphoteric metals like Zn and Al.

2NaOH + Zn → Na₂ZnO₂ + H₂↑ (Sodium zincate)
2NaOH + 2Al + 2H₂O → 2NaAlO₂ + 3H₂↑ (Sodium aluminate)

Non-metals like silicon can also react with bases: Si + 2NaOH + H₂O → Na₂SiO₃ + 2H₂↑ (Sodium silicate).

📊 Chemical Properties Summary Table

Reaction Type Metals Non-Metals
With Oxygen Form basic/amphoteric oxides Form acidic oxides
With Water Produce metal hydroxide + H₂ Generally no reaction
With Acids Produce salt + H₂ gas No reaction (generally)
With Bases Only amphoteric metals (Zn, Al) react Some non-metals (Si, C) react
Displacement More reactive displaces less reactive

📊 Reactivity Series of Metals

The reactivity series (also called the activity series) is a list of metals arranged in order of decreasing reactivity. The most reactive metal is at the top, and the least reactive is at the bottom. This series is fundamental to understanding displacement reactions, extraction methods, and corrosion.

🔺 Reactivity Series (Top to Bottom)

Metal Symbol Reactivity Reaction with O₂ Reaction with H₂O Reaction with Acids Extraction Method
Potassium K 🔥 Most Reactive Burns vigorously (stored under kerosene) Violent — catches fire Explosive Electrolysis (Molten ore)
Sodium Na 🔥↑ Burns vigorously (stored under kerosene) Violent — catches fire Explosive Electrolysis
Calcium Ca 🔥↑ Burns readily Less violent — H₂ bubbles Vigorous Electrolysis
Magnesium Mg ⚡↑ Burns with brilliant white flame Reacts with hot water/steam Vigorous Electrolysis
Aluminium Al ⚡↑ Forms protective oxide layer No reaction Vigorous Electrolysis
Zinc Zn ⚡→ Burns when heated React with steam Moderate (H₂ gas) Reduction with C/CO
Iron Fe ⚡↓ Burns when strongly heated Very slow (steam only) Moderate Reduction with CO
Tin Sn ⚡↓ Reacts slowly No reaction Slow Reduction with C
Lead Pb ⚡↓ Reacts slowly when heated No reaction Slow Reduction with C
Copper Cu 🐢↑ Reacts only on prolonged heating No reaction Does not react Roasting + Reduction
Silver Ag 🐢→ Does not react No reaction Does not react Native ore (free state)
Gold Au 🐢↓ Least Reactive ❄️ Does not react No reaction Does not react Native ore (free state)

🔑 Reactivity Series — Mnemonic

📘 Mnemonic: “Please Stop Calling Me A Zebra I Like Cool Silver Gold”

Potassium → Sodium → Calcium → Magnesium → Aluminium → Zinc → Iron → Lead → Copper → Silver → Gold

⚡ Displacement Reactions Based on Reactivity

Displacement reaction: A more reactive metal displaces a less reactive metal from its salt solution. This principle is used in many applications and is a very common exam question.

Fe + CuSO₄ → FeSO₄ + Cu (Iron displaces copper)
Zn + CuSO₄ → ZnSO₄ + Cu (Zinc displaces copper)
Cu + 2AgNO₃ → Cu(NO₃)₂ + 2Ag (Copper displaces silver)

Observation: When iron is placed in blue copper sulphate solution —

  • The blue colour of CuSO₄ solution fades gradually.
  • A reddish-brown coating of copper is deposited on the iron nail.
  • This is because Fe is more reactive than Cu and displaces it.

🔬 The Reactivity Series — Why it Matters

  • Displacement Reactions: Predict whether one metal can displace another from its salt solution.
  • Extraction of Metals: Determines the method used to extract a metal from its ore.
  • Corrosion: More reactive metals corrode more easily.
  • Electrochemical Series: Basis for Galvanic cells and batteries.

⛏️ Extraction of Metals (Metallurgy)

Metallurgy is the process of extracting metals from their ores and refining them for use. The method of extraction depends on the position of the metal in the reactivity series.

🏭 Step-by-Step Process: Ore to Pure Metal

Step 1: Mining → Crushing → Concentration (Enrichment of Ore)

The ore obtained from the earth’s crust contains impurities like sand, clay, and rocks (called gangue). The ore must be concentrated to remove gangue before further processing.

  • Gangue: The unwanted earthy impurities (sand, clay, rock particles) present in the ore.
  • Concentration: The process of removing gangue from the ore to increase the percentage of metal in the ore.

Methods of Concentration

Method Principle Used For
Hand-picking Manual separation of visible impurities Large pieces of gangue
Hydraulic Washing (Gravity Separation) Difference in densities of ore and gangue Oxide ores (e.g., iron ore)
Froth Flotation Wetting properties — ore particles attach to froth Sulphide ores (e.g., ZnS, CuFeS₂)
Magnetic Separation Magnetic properties of ore vs gangue Iron ores (magnetite, hematite)
Leaching Selective dissolution of ore in a suitable reagent Bauxite (Al ore) — Bayer’s process

📘 Bayer’s Process (Leaching of Bauxite)

Bauxite (Al₂O₃·2H₂O) is dissolved in hot NaOH solution. Al₂O₃ dissolves to form NaAlO₂ (sodium aluminate), while impurities (Fe₂O₃, SiO₂) remain undissolved. On cooling and CO₂ treatment, pure Al(OH)₃ precipitates: NaAlO₂ + 2H₂O + CO₂ → Al(OH)₃ + NaHCO₃

Step 2: Conversion of Concentrated Ore into Metal Oxide

The concentrated ore is converted into its oxide form, which is then reduced to the metal. This is done by either roasting (for sulphide ores) or calcination (for carbonate/hydroxide ores).

Process Definition Used For Example Equation
Roasting Heating ore strongly in the presence of excess air/oxygen Sulphide ores 2ZnS + 3O₂ → 2ZnO + 2SO₂↑
Calcination Heating ore strongly in the absence/limited supply of air Carbonate/hydroxide ores CaCO₃ → CaO + CO₂↑ (limestone)
Roasting of Copper Ore: 2CuFeS₂ + 4O₂ → Cu₂S + 2FeO + 3SO₂↑
Calcination of Zinc Carbonate: ZnCO₃ → ZnO + CO₂↑
Calcination of Bauxite: 2Al(OH)₃ → Al₂O₃ + 3H₂O

Step 3: Reduction of Metal Oxide to Metal

The metal oxide is reduced to the free metal. The method depends on the reactivity of the metal:

A. Reduction by Carbon (Smelting) — for moderately reactive metals

Metals like Zn, Fe, Pb, Sn are extracted by heating their oxides with carbon (coke). Carbon acts as a reducing agent, removing oxygen from the metal oxide.

ZnO + C → Zn + CO↑ (Reduction of zinc oxide)
Fe₂O₃ + 3CO → 2Fe + 3CO₂↑ (Reduction of iron ore in blast furnace)
PbO + C → Pb + CO↑ (Reduction of lead oxide)

Blast Furnace for Iron: Iron is extracted from haematite (Fe₂O₃) using carbon monoxide as the reducing agent. The blast furnace operates at ~1900°C and produces molten iron (pig iron).

B. Reduction by Electrolysis — for highly reactive metals

Metals that are highly reactive (K, Na, Ca, Mg, Al) cannot be reduced by carbon because they have a strong affinity for oxygen. They are extracted by electrolytic reduction — passing electricity through their molten (fused) compounds.

Electrolysis of NaCl: 2NaCl(l) → 2Na + Cl₂↑ (at anode)
Electrolysis of Al₂O₃: 2Al₂O₃ → 4Al + 3O₂↑ (Hall-Héroult process)

C. Reduction by Aluminium (Thermite Process) — for high melting metals

Aluminium is a strong reducing agent. It is used to reduce oxides of metals like Cr, Mn, Fe in the Thermite process.

Fe₂O₃ + 2Al → 2Fe + Al₂O₃ + Heat (Thermite reaction)

The thermite reaction produces enormous heat (∼3000°C), enough to weld railway tracks and extract metals like chromium and manganese.

🎯 Exam Tip: The thermite reaction (Fe₂O₃ + 2Al) is a classic exam question. It is an exothermic displacement reaction used for: (a) welding railway tracks, (b) extracting high-melting metals like Cr and Mn.

Step 4: Refining of Metals

The metal obtained after reduction is impure. It is refined to obtain high-purity metal. The most common method is electrolytic refining.

🔋 Electrolytic Refining

Component Details
Anode Impure metal (to be purified)
Cathode Pure metal strip
Electrolyte Aqueous solution of the metal’s salt
Reaction at Anode Impure metal dissolves: M → Mⁿ⁺ + ne⁻
Reaction at Cathode Pure metal deposits: Mⁿ⁺ + ne⁻ → M

📘 Example — Copper Refining

Electrolyte: CuSO₄ + dilute H₂SO₄
Anode (Impure Cu): Cu → Cu²⁺ + 2e⁻
Cathode (Pure Cu): Cu²⁺ + 2e⁻ → Cu
Impurities (Ag, Au, Pt) settle as anode mud — valuable byproducts!

🔄 Complete Extraction Flowchart

Ore → Concentration (remove gangue) → Roasting/Calcination (to oxide) → Reduction (C/Electrolysis/Thermite) → Refining (Electrolytic) → Pure Metal:

📊 Extraction Method Based on Reactivity Series

Position in Series Metals Extraction Method Example
Top (Highly reactive) K, Na, Ca, Mg, Al Electrolytic reduction NaCl(l) → Na + Cl₂
Middle (Moderately reactive) Zn, Fe, Pb, Sn Reduction with C/CO ZnO + C → Zn + CO
Bottom (Least reactive) Cu, Ag, Au, Pt Chemical reduction / Native state Roasting of Cu₂S → Cu

🔧 Corrosion — Rusting, Tarnishing & Prevention

Corrosion is the gradual destruction of metals by chemical or electrochemical reaction with their environment. It is a natural process that converts refined metals into more stable compounds (oxides, hydroxides, sulphides).

🟤 Rusting of Iron

Rusting: The corrosion of iron, forming reddish-brown hydrated iron(III) oxide (Fe₂O₃·xH₂O), commonly called rust.

Conditions required for rusting: Iron rusts only when both oxygen (air) AND water are present.

4Fe + 3O₂ + 2xH₂O → 2Fe₂O₃·xH₂O (Rust)

🔬 Activity to Show Conditions for Rusting

Take three test tubes with iron nails:

  • Test tube A: Nail + water (air excluded by oil layer) → No rust (air needed!)
  • Test tube B: Nail + dry air (with anhydrous CaCl₂) → No rust (water needed!)
  • Test tube C: Nail + both water and air → Rust forms!
🎯 Exam Tip: This experiment proving that BOTH air (O₂) and water are necessary for rusting is a 3-5 mark question in MP Board exams. Remember: oil prevents air contact, CaCl₂ absorbs moisture.

⚪ Tarnishing of Other Metals

Metal Tarnish Compound Formed Colour
Silver (Ag) Black tarnish on silver utensils/jewellery Ag₂S (Silver sulphide) Black
Copper (Cu) Green coating on copper vessels CuCO₃·Cu(OH)₂ (Basic copper carbonate) Green
Aluminium (Al) White protective layer Al₂O₃ (Aluminium oxide) White
Lead (Pb) Grey coating PbO + PbCO₃ Grey

🛡️ Prevention of Corrosion

Corrosion causes massive economic losses. Several methods are used to prevent it:

1️⃣ Galvanization

Galvanization: The process of coating iron or steel with a layer of zinc to prevent rusting.
  • Zinc is more reactive than iron, so it corrodes preferentially (sacrificial protection).
  • Even if the zinc coating is scratched, the zinc corrodes first, protecting the iron underneath.
  • Used for: iron buckets, pipes, roofs, automobile parts.

2️⃣ Electroplating

Coating a metal with a thin layer of another metal (Cr, Ni, Cu, Ag, Au) using electrolysis.

  • Chrome plating: Car bumpers, taps, kitchen appliances — shiny and rust-resistant.
  • Silver/Gold plating: Decorative items, jewellery.
  • Tin plating: Food cans (tin is non-toxic and corrosion-resistant).

3️⃣ Alloying

Mixing metals with other elements to form alloys that resist corrosion.

  • Stainless steel: Fe + Cr + Ni — does not rust. Chromium forms a protective oxide layer.
  • Brass: Cu + Zn — more corrosion-resistant than pure copper.
  • Bronze: Cu + Sn — ancient alloy, highly durable.

4️⃣ Paint, Oil & Grease

Applying a protective layer that prevents contact with air and moisture.

  • Paint: Used on iron gates, bridges, ships.
  • Oil/Grease: Used on machine parts, tools.
  • Plastic coating: Used on handles, garden furniture.

5️⃣ Sacrificial Protection

Attaching a more reactive metal (Mg, Zn) to the structure to be protected. The more reactive metal corrodes first, saving the structure.

  • Used for: underground pipelines, ship hulls, water tanks.
  • Magnesium blocks are attached to the hulls of ships to prevent corrosion of the steel hull.

📊 Corrosion Prevention Methods Summary

Method Principle Example Application
Galvanization Zinc coating — sacrificial protection Iron buckets, pipes, roofs
Electroplating Thin layer of corrosion-resistant metal Chrome plating on car parts
Alloying Mixing metals for corrosion resistance Stainless steel (Fe + Cr + Ni)
Painting/Oiling Physical barrier against air + water Bridges, machines, tools
Sacrificial Anode More reactive metal attached Ship hulls, underground pipes
Anodizing Thickening natural oxide layer (Al) Aluminium window frames

📝 Practice Questions (With Answers)

  1. Q1: An element A reacts with oxygen to form compound B which has high melting point. This compound is soluble in water and turns red litmus blue. Identify element A and compound B. Write the balanced equation and state the nature of B.
  2. Q2: Why is sodium metal stored under kerosene? What happens when a small piece of sodium is dropped into water? Write the balanced chemical equation.
  3. Q3: Explain the extraction of iron from its ore. Describe the role of carbon monoxide in the blast furnace and write the chemical equation involved.
  4. Q4: What is galvanization? Why is zinc used for galvanizing iron even though it is more reactive than iron? Explain the principle behind this method.
  5. Q5: A metal M does not react with dilute HCl but reacts with oxygen to form a black compound. When this black compound is heated with hydrogen gas, it forms reddish-brown M again. Identify M and write all chemical equations.
  6. Q6: Arrange the following metals in decreasing order of reactivity: Zn, Cu, Na, Fe, Ag, Al, Ca. Which of these metals would react with cold water? Which would not react with dilute HCl?

✅ Answer Key

  • A1: A = Mg (Magnesium), B = MgO (Magnesium oxide).
    2Mg + O₂ → 2MgO. MgO is basic in nature — turns red litmus blue.
    MgO + H₂O → Mg(OH)₂ (magnesium hydroxide — a base).
  • A2: Sodium is stored under kerosene to prevent contact with air (O₂) and moisture (H₂O) as it reacts explosively with both.
    2Na + 2H₂O → 2NaOH + H₂↑
    Sodium catches fire spontaneously on water — the reaction is highly exothermic.
  • A3: Iron is extracted from haematite (Fe₂O₃) in a blast furnace using coke (C) and limestone (CaCO₃). Coke burns to form CO, which reduces Fe₂O₃ to Fe:
    Fe₂O₃ + 3CO → 2Fe + 3CO₂↑
    Limestone removes impurities as slag (CaSiO₃).
  • A4: Galvanization is coating iron/steel with a layer of zinc. Zinc is more reactive than iron, so it corrodes preferentially (sacrificial protection). Even if scratched, zinc corrodes first, protecting the iron underneath. This works because Zn is above Fe in the reactivity series.
  • A5: M = Cu (Copper).
    2Cu + O₂ → 2CuO (black copper oxide)
    CuO + H₂ → Cu + H₂O (hydrogen reduces CuO to reddish-brown Cu)
    Cu does not react with dilute HCl because it is below hydrogen in the reactivity series.
  • A6: Na → Ca → Al → Zn → Fe → Cu → Ag (decreasing order).
    Na and Ca react with cold water. Ag and Cu do not react with dilute HCl.

📋 Previous Year Questions (2017–2026)

Year Question Marks
2026 Explain the process of electrolytic refining of copper with a neat labelled diagram. What happens to the impurities present in the anode? 5
2025 What is the reactivity series of metals? Explain with examples how a more reactive metal displaces a less reactive metal from its salt solution. Write any two displacement reactions. 4
2024 What is corrosion? Describe the conditions necessary for rusting of iron with a diagram. How can rusting be prevented? 5
2023 Differentiate between metals and non-metals on the basis of: (a) malleability, (b) ductility, (c) conductivity, (d) sonority. Give one example of each. 3
2022 Explain the thermite reaction with a balanced chemical equation. Write its two applications in daily life. 3
2021 What is an amalgam? How is sodium amalgam prepared? Write the chemical equation for the extraction of sodium by electrolysis of molten NaCl. 3
2020 Describe the extraction of aluminium from bauxite ore. Write the reactions involved in Bayer’s process and the Hall-Héroult process. 5
2019 An iron nail is placed in copper sulphate solution. What colour changes do you observe? Give reason. Write the balanced chemical equation. 3
2018 What are amphoteric oxides? Give two examples. Write two balanced equations showing the amphoteric nature of aluminium oxide. 2
2017 What is galvanization? Why is it preferred over ordinary painting for protection of iron from rusting? 3

MP Board Class 10 Science Chapter 2: Acids, Bases & Salts Notes 2027 — Properties, pH Scale, Indicators & PYQs

Chapter 2: Acids, Bases & Salts is a high-weightage chapter in MP Board Class 10 Science, contributing 10–12 marks in the annual board exam. This chapter covers the classification of substances as acidic or basic, the pH scale, indicators, reaction of acids and bases with metals, carbonates, and each other (neutralization), and the preparation and uses of important salts. Questions range from 1-mark MCQs to 5-mark comprehensive answers. Understanding the reaction patterns and salt preparation methods is essential for board success.

🧪 Properties of Acids vs Bases

Acids and bases are two fundamental categories of chemical substances with opposing properties. Understanding their differences is critical for predicting chemical reactions and their applications in daily life.

📊 Comparison Table: Acids vs Bases

Property Acids Bases
Taste Sour (e.g., lemon, vinegar) Bitter (e.g., soap, baking soda)
Touch May be corrosive, can burn skin Soapy or slippery to touch
Litmus Test Turn blue litmus red Turn red litmus blue
pH Range 0 to 6.9 (below 7) 7.1 to 14 (above 7)
Reaction with Metals Produce H₂ gas (e.g., Zn + HCl → ZnCl₂ + H₂) No reaction with most metals
Reaction with Carbonates Produce CO₂ gas (e.g., CaCO₃ + HCl → CaCl₂ + H₂O + CO₂) No reaction with carbonates
Reaction with Bases/Acids Neutralize bases to form salt + water Neutralize acids to form salt + water
Conductivity Conduct electricity in aqueous solution Conduct electricity in aqueous solution
Examples HCl, H₂SO₄, HNO₃, CH₃COOH, H₂CO₃ NaOH, KOH, Ca(OH)₂, NH₄OH, Mg(OH)₂
Natural Sources Citrus fruits, vinegar, stomach acid Soap, lime water, antacids

🔬 Reaction of Acids with Metals

Acids react with active metals (like Zn, Fe, Mg, Al) to produce hydrogen gas and a salt.

  • Zn + 2HCl → ZnCl₂ + H₂↑ (Zinc reacts with hydrochloric acid)
  • Mg + H₂SO₄ → MgSO₄ + H₂↑ (Magnesium reacts with sulphuric acid)
  • 2Al + 6HCl → 2AlCl₃ + 3H₂↑ (Aluminium reacts with hydrochloric acid)
🎯 Exam Tip: The hydrogen gas produced can be tested by bringing a burning matchstick near it — it burns with a pop sound. This “pop test” is frequently asked in practical-based questions.

⚗️ Reaction of Acids with Metal Carbonates & Bicarbonates

Acids react with carbonates and bicarbonates to produce carbon dioxide gas, water, and a salt.

  • CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂↑ (Limestone reacts with HCl)
  • NaHCO₃ + HCl → NaCl + H₂O + CO₂↑ (Baking soda reacts with HCl)
  • Na₂CO₃ + 2HCl → 2NaCl + H₂O + CO₂↑ (Washing soda reacts with HCl)
🎯 Exam Tip: CO₂ gas turns lime water milky: Ca(OH)₂ + CO₂ → CaCO₃ + H₂O. This is a common confirmatory test asked in exams.

🤝 Neutralization Reaction (Acid + Base)

When an acid and a base react, they neutralize each other to form a salt and water. This is called a neutralization reaction.

  • HCl + NaOH → NaCl + H₂O (Hydrochloric acid + Sodium hydroxide)
  • H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O (Sulphuric acid + Sodium hydroxide)
  • HCl + NH₄OH → NH₄Cl + H₂O (Hydrochloric acid + Ammonium hydroxide)

📘 Everyday Example — Antacids

When you have acidity (excess HCl in the stomach), you take antacids like Milk of Magnesia (Mg(OH)₂) or Eno (NaHCO₃). The base neutralizes excess acid: Mg(OH)₂ + 2HCl → MgCl₂ + 2H₂O.

🧂 Reaction of Acids & Bases — Summary Flow

Reaction Type Reactants Products Example
Acid + Metal Acid + Active metal Salt + H₂ gas Zn + 2HCl → ZnCl₂ + H₂
Acid + Carbonate Acid + Metal carbonate Salt + H₂O + CO₂ CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂
Acid + Bicarbonate Acid + Metal bicarbonate Salt + H₂O + CO₂ NaHCO₃ + HCl → NaCl + H₂O + CO₂
Acid + Base Acid + Base Salt + H₂O HCl + NaOH → NaCl + H₂O
Base + Metal Base + Certain metals (e.g., Zn, Al) Salt + H₂ gas 2NaOH + Zn → Na₂ZnO₂ + H₂↑

⚗️ Reaction of Base with Metals

Some bases (alkalis) react with certain reactive metals like Zn and Al to produce hydrogen gas.

  • 2NaOH + Zn → Na₂ZnO₂ + H₂↑ (Sodium zincate is formed)
  • 2NaOH + 2Al + 2H₂O → 2NaAlO₂ + 3H₂↑ (Sodium aluminate is formed)
🎯 Exam Tip: Note: Not all bases react with metals. Only strong alkalis (like NaOH, KOH) react with amphoteric metals (Zn, Al). This is a commonly tested distinction.

📊 pH Scale with Examples

The pH scale (potential of Hydrogen) is a logarithmic scale used to specify the acidity or basicity of an aqueous solution. It ranges from 0 to 14, where 7 represents a neutral solution.

  • pH < 7: Acidic solution — lower the pH, stronger the acid
  • pH = 7: Neutral solution (pure water)
  • pH > 7: Basic (alkaline) solution — higher the pH, stronger the base

🧪 pH Values of Common Substances

Substance pH Value Nature
Gastric juices (Stomach) ~1.0 Strongly Acidic
Lemon juice ~2.0–2.3 Acidic
Vinegar ~3.0 Acidic
Orange juice ~3.5 Acidic
Tomato juice ~4.0 Acidic
Coffee ~5.0 Weakly Acidic
Milk ~6.4 Slightly Acidic
Pure water 7.0 Neutral
Blood ~7.4 Slightly Basic
Seawater ~8.0 Basic
Baking soda solution ~8.3 Basic
Antacid (Milk of Magnesia) ~10.5 Basic
Lime water (Ca(OH)₂) ~11.0 Strongly Basic
NaOH solution (1M) ~14.0 Very Strongly Basic

🔬 Importance of pH in Daily Life

  • Human Body: Blood pH must remain around 7.35–7.45. Stomach pH (~1.5–3.5) helps digestion. pH imbalance can cause health issues.
  • Plants: Most plants grow best at soil pH 6.5–7.5. Acidic soil is treated with lime (CaO).
  • Digestion: Our stomach produces HCl for digestion. Excess causes acidity, treated with antacids (bases).
  • Tooth Decay: Bacteria produce acids (pH < 5.5) that demineralize tooth enamel. Toothpaste (basic) neutralizes the acid.
  • Bee Sting: Bee sting injects formic acid (acidic) — treated with baking soda (base).
  • Wasp Sting: Wasp sting is alkaline — treated with vinegar (acid).

📘 The pH Formula

The pH of a solution is defined as the negative logarithm (base 10) of the hydrogen ion concentration: pH = –log[H⁺]. For example, if [H⁺] = 10⁻³ M, pH = 3. A ten-fold change in [H⁺] changes pH by 1 unit.

🎨 Indicators (Litmus, Phenolphthalein, Methyl Orange)

Indicators are substances that change colour in acidic or basic media. They help us determine whether a substance is acidic or basic without tasting or touching it.

🔵🔴 Types of Indicators

🧪 Natural Indicators

  • Litmus: Extracted from lichens. Blue litmus turns red in acid; red litmus turns blue in base.
  • Turmeric: Yellow in acid/neutral, turns red in base.
  • Red Cabbage: Contains anthocyanin — red in acid, greenish-yellow in base.
  • China Rose (Hibiscus): Dark magenta in acid, bright green in base.
  • Methyl Orange: Synthetic indicator — red in acid, yellow in base.

📋 Indicator Colour Chart

Indicator Colour in Acid Colour in Base Colour in Neutral
Blue Litmus Turns Red No change (Blue) Blue
Red Litmus No change (Red) Turns Blue Red
Phenolphthalein Colourless Turns Pink Colourless
Methyl Orange Turns Red Turns Yellow Orange
Turmeric Yellow Red Yellow
Red Cabbage Extract Red Greenish-Yellow Purple/Blue

🧪 pH Indicators — Universal Indicator

A universal indicator is a mixture of several indicators that gives a distinct colour for each pH value. By comparing the colour with a standard pH colour chart, the approximate pH of a solution can be determined.

  • Red → Strongly acidic (pH 1–2)
  • Orange/Yellow → Moderately acidic (pH 3–5)
  • Green → Neutral (pH 7)
  • Blue → Moderately basic (pH 8–10)
  • Violet → Strongly basic (pH 11–14)

🧪 Olfactory Indicators

Substances whose smell changes in acidic or basic media are called olfactory indicators.

  • Onion: Characteristic smell vanishes when treated with a base.
  • Vanilla extract: Smell vanishes when treated with a base.
🎯 Exam Tip: MP Board often asks: “Name two olfactory indicators” or “How can you test whether a substance is acid or base without using litmus?” Answer: Onion and vanilla extract.

🧂 Common Salts — Preparation & Uses

A salt is an ionic compound formed by the neutralization reaction between an acid and a base. Salts consist of positive ions (cations) from the base and negative ions (anions) from the acid.

1️⃣ Sodium Chloride (NaCl) — Common Salt

Sodium Chloride (NaCl): Common salt or table salt. It is the most important salt obtained from seawater and salt mines.

Preparation

  • Obtained by evaporation of seawater in salt pans
  • Also mined from underground salt deposits (rock salt)
  • Impure NaCl is dissolved in water, filtered, and recrystallized to get pure NaCl

Uses

  • Essential seasoning in food (table salt)
  • Preservation of fish, meat, and pickles
  • Raw material for manufacturing Na₂CO₃, NaOH, Cl₂, HCl
  • Used in the chlor-alkali process to manufacture NaOH and Cl₂

⚡ Chlor-Alkali Process

When electricity is passed through an aqueous solution of NaCl (brine), it decomposes to form NaOH, Cl₂, and H₂.

Chlor-Alkali Process: 2NaCl(aq) + 2H₂O(l) → 2NaOH(aq) + Cl₂(g) + H₂(g)

This is an important industrial process and is frequently asked in MP Board exams.

2️⃣ Sodium Bicarbonate (NaHCO₃) — Baking Soda

Sodium Bicarbonate (NaHCO₃): Baking soda — a mild, non-corrosive base used in cooking and cleaning.

Preparation

Prepared by Solvay process. A cold and concentrated solution of sodium chloride is treated with ammonia and carbon dioxide:

  • NaCl + NH₃ + CO₂ + H₂O → NaHCO₃ + NH₄Cl
  • NaHCO₃ is sparingly soluble in water, so it precipitates out

Uses

  • Used in baking powder (NaHCO₃ + tartaric acid) — produces CO₂ that makes cakes and bread fluffy
  • Used as an antacid to neutralize excess stomach acid
  • Used in fire extinguishers — produces CO₂ gas when heated
  • Used in cleaning and as a mild disinfectant

🔥 Decomposition of Baking Soda

When heated, baking soda decomposes to produce CO₂:

Heating of NaHCO₃: 2NaHCO₃ → Na₂CO₃ + H₂O + CO₂↑

3️⃣ Bleaching Powder (CaOCl₂) — Calcium Oxychloride

Bleaching Powder (CaOCl₂): Also called chloride of lime. A yellowish-white powder with a strong smell of chlorine.

Preparation

Prepared by passing chlorine gas over dry slaked lime (Calcium hydroxide):

Preparation of Bleaching Powder: Ca(OH)₂ + Cl₂ → CaOCl₂ + H₂O

Conditions: Dry slaked lime, low temperature

Uses

  • Used for bleaching cotton, linen, wood pulp in paper industry
  • Used as a disinfectant for water purification and sanitation
  • Used in the manufacture of chloroform (CHCl₃)
  • Used for bleaching in textile and laundry industries
🎯 Exam Tip: When bleaching powder is exposed to air, it reacts with CO₂ to release chlorine gas: CaOCl₂ + CO₂ → CaCO₃ + Cl₂. This is why it has a chlorine-like smell.

4️⃣ Gypsum (CaSO₄·2H₂O) — Calcium Sulphate Dihydrate

Gypsum (CaSO₄·2H₂O): A naturally occurring mineral. On heating to 373 K, it loses water molecules to form Plaster of Paris.

Preparation of Plaster of Paris

Heating of Gypsum: CaSO₄·2H₂O → CaSO₄·½H₂O + 1½H₂O (at 373K)

Plaster of Paris (CaSO₄·½H₂O) is a white powder that sets into a hard mass when mixed with water.

Uses of Gypsum

  • Used in the manufacture of cement (retards setting time)
  • Used as a fertilizer (source of calcium and sulphur)
  • Used in making chalk and blackboard
  • Used in plastering walls and ceilings

Uses of Plaster of Paris

  • Making statues, toys, and decorative items
  • Used in orthopaedics for setting fractured bones
  • Used in construction for false ceilings and decorative mouldings

5️⃣ Sodium Carbonate (Na₂CO₃·10H₂O) — Washing Soda

Sodium Carbonate (Na₂CO₃·10H₂O): Washing soda — decahydrate form of sodium carbonate. Prepared by heating baking soda.

Preparation

Prepared by heating baking soda (NaHCO₃), followed by recrystallization:

  • Step 1: 2NaHCO₃ → Na₂CO₃ + H₂O + CO₂↑ (heating)
  • Step 2: Na₂CO₃ + 10H₂O → Na₂CO₃·10H₂O (recrystallization from water)

Uses

  • Used as a cleaning agent (washing soda) for laundry
  • Used in the manufacture of glass, soap, and paper
  • Used for removing permanent hardness of water
  • Used in the Solvay process for manufacturing NaHCO₃

📊 Summary Table: Common Salts

Salt Formula Common Name Preparation Summary Key Use
Sodium Chloride NaCl Table Salt / Common Salt Evaporation of seawater Food seasoning, preservation
Sodium Bicarbonate NaHCO₃ Baking Soda Solvay process (NaCl + NH₃ + CO₂) Baking, antacid, fire extinguisher
Sodium Carbonate Na₂CO₃·10H₂O Washing Soda Heating NaHCO₃ + recrystallization Cleaning, glass making
Calcium Oxychloride CaOCl₂ Bleaching Powder Ca(OH)₂ + Cl₂ Bleaching, disinfectant
Calcium Sulphate CaSO₄·2H₂O Gypsum Naturally occurring mineral Cement, POP, plaster

📝 Practice Questions (With Answers)

  1. Q1: What happens when a piece of zinc metal is dropped into dilute hydrochloric acid? Write the balanced chemical equation and name the gas evolved.
  2. Q2: Two solutions A and B have pH values of 3 and 11 respectively. Which of these is acidic and which is basic? Calculate the hydrogen ion concentration of each.
  3. Q3: Explain the preparation of bleaching powder with a balanced chemical equation. Write any two uses of bleaching powder.
  4. Q4: What is the difference between baking soda (NaHCO₃) and washing soda (Na₂CO₃·10H₂O)? How can baking soda be converted into washing soda?
  5. Q5: Why does blue litmus turn red when dipped in vinegar? Explain using the concept of acids and indicators.

✅ Answer Key

  • A1: Zinc reacts with HCl to produce zinc chloride and hydrogen gas.
    Zn + 2HCl → ZnCl₂ + H₂↑
    Gas: Hydrogen (H₂). It burns with a pop sound near a flame.
  • A2: Solution A (pH 3) is acidic. Solution B (pH 11) is basic.
    [H⁺] for A = 10⁻³ M, [H⁺] for B = 10⁻¹¹ M.
  • A3: Ca(OH)₂ + Cl₂ → CaOCl₂ + H₂O. Uses: (i) Bleaching cotton and linen, (ii) Disinfecting drinking water.
  • A4: NaHCO₃ is baking soda (mild base, used in food). Na₂CO₃·10H₂O is washing soda (strong base, used for cleaning).
    Conversion: 2NaHCO₃ → Na₂CO₃ + H₂O + CO₂↑ (heating), followed by Na₂CO₃ + 10H₂O → Na₂CO₃·10H₂O.
  • A5: Vinegar contains acetic acid (CH₃COOH). Acids release H⁺ ions in solution which react with the colouring agent in blue litmus, turning it red.

📋 Previous Year Questions (2017–2026)

Year Question Marks
2026 Write balanced chemical equations for: (a) Sodium bicarbonate is heated, (b) Bleaching powder reacts with dilute HCl. Name each type of reaction. 3
2025 What is the pH of a neutral solution? If a solution has pH = 1, how many times more acidic is it than a solution with pH = 3? 2
2024 Identify the acid and base that form sodium chloride. What is the nature of NaCl solution? Explain with pH value. 3
2023 Define neutralization reaction. Give two examples from daily life where neutralization is used. 3
2022 Why does blue litmus turn red in acid? What colour change is observed when red litmus is dipped in NaOH solution? 2
2021 Write the chemical formula of bleaching powder. How is it prepared? Write any two uses. 3
2020 Distinguish between baking soda and washing soda on the basis of: (a) chemical formula, (b) preparation method, (c) one use each. 4
2019 Name the products formed when hydrochloric acid reacts with: (i) zinc metal, (ii) sodium carbonate, (iii) sodium hydroxide. 3
2018 What is universal indicator? How is it different from litmus paper? Name one natural indicator other than litmus. 2
2017 What is gypsum? What happens when it is heated at 373 K? Write the chemical equation and mention one use of the product formed. 3

MP Board Class 10 Maths Chapter 7: Coordinate Geometry — Notes, Formulas & Practice Questions

📐 MP Board Class 10 Maths — Chapter 7: निर्देशांक ज्यामिति (Coordinate Geometry)


📌 Key Concepts & Formulas

1. निर्देशांक पद्धति (Coordinate System)

निर्देशांक तल (Coordinate Plane): X-अक्ष (क्षैतिज) और Y-अक्ष (ऊर्ध्वाधर) के परस्पर लंबवत प्रतिच्छेद से बना तल।

  • मूल बिंदु (Origin): O(0, 0) — जहाँ X-अक्ष और Y-अक्ष मिलते हैं
  • भुज (Abscissa): किसी बिंदु का X-निर्देशांक (x-coordinate)
  • कोटि (Ordinate): किसी बिंदु का Y-निर्देशांक (y-coordinate)
  • बिंदु P(x, y) में: x = X-अक्ष से दूरी (भुज), y = Y-अक्ष से दूरी (कोटि)
  • मूल बिंदु के निर्देशांक = (0, 0)
चतुर्थांश (Quadrant) चिह्न (Sign) उदाहरण
प्रथम (I) (+, +) (3, 5)
द्वितीय (II) (-, +) (-3, 5)
तृतीय (III) (-, -) (-3, -5)
चतुर्थ (IV) (+, -) (3, -5)

2. दो बिंदुओं के बीच की दूरी (Distance Formula)

दो बिंदुओं P(x₁, y₁) और Q(x₂, y₂) के बीच की दूरी:

[
PQ = \sqrt{(x_2 – x_1)^2 + (y_2 – y_1)^2}
]

  • मूल बिंदु O(0, 0) से बिंदु P(x, y) की दूरी = (\sqrt{x^2 + y^2})

3. विभाजन सूत्र (Section Formula)

आंतरिक विभाजन (Internal Division)

बिंदु P(x, y) जो रेखाखंड AB को m₁ : m₂ के अनुपात में आंतरिक रूप से विभाजित करता है:

[
P(x, y) = \left( \frac{m_1x_2 + m_2x_1}{m_1 + m_2}, \frac{m_1y_2 + m_2y_1}{m_1 + m_2} \right)
]

मध्य-बिंदु (Midpoint Formula) — जब m₁ = m₂ = 1:

[
M(x, y) = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
]


4. त्रिभुज का क्षेत्रफल (Area of Triangle)

शीर्षों A(x₁, y₁), B(x₂, y₂), C(x₃, y₃) वाले त्रिभुज का क्षेत्रफल:

[
\text{Area} = \frac{1}{2} \left| x_1(y_2 – y_3) + x_2(y_3 – y_1) + x_3(y_1 – y_2) \right|
]

  • यदि क्षेत्रफल = 0, तो तीनों बिंदु संरेख (collinear) हैं।

5. संरेखता की शर्त (Collinearity Condition)

तीन बिंदु A, B, C संरेख होंगे यदि:
– इनसे बने त्रिभुज का क्षेत्रफल = 0
या
– AB + BC = AC (दूरी सूत्र से)


📝 Solved Examples (5)

Example 1: दो बिंदुओं के बीच दूरी ज्ञात करना

बिंदु A(3, 4) और B(7, 1) के बीच की दूरी ज्ञात करें।

हल:

दूरी सूत्र का प्रयोग:
[
AB = \sqrt{(x_2 – x_1)^2 + (y_2 – y_1)^2}
]
[
AB = \sqrt{(7 – 3)^2 + (1 – 4)^2}
]
[
AB = \sqrt{4^2 + (-3)^2}
]
[
AB = \sqrt{16 + 9} = \sqrt{25} = \textbf{5 इकाई}
]


Example 2: बिंदु की अक्षों से दूरी

बिंदु P(-4, 3) की X-अक्ष और Y-अक्ष से दूरी ज्ञात करें।

हल:

X-अक्ष से दूरी = |y-निर्देशांक| = |3| = 3 इकाई
Y-अक्ष से दूरी = |x-निर्देशांक| = |-4| = 4 इकाई

मूल बिंदु से दूरी = (\sqrt{(-4)^2 + 3^2} = \sqrt{16 + 9} = \sqrt{25} = \textbf{5 इकाई}) ✅


Example 3: विभाजन सूत्र — बिंदु के निर्देशांक ज्ञात करना

बिंदु P, बिंदुओं A(2, -3) और B(7, 7) को मिलाने वाले रेखाखंड को 2 : 3 के अनुपात में आंतरिक रूप से विभाजित करता है। P के निर्देशांक ज्ञात करें।

हल:

m₁ = 2, m₂ = 3
A(x₁, y₁) = (2, -3), B(x₂, y₂) = (7, 7)

[
x = \frac{m_1x_2 + m_2x_1}{m_1 + m_2} = \frac{2(7) + 3(2)}{2 + 3} = \frac{14 + 6}{5} = \frac{20}{5} = 4
]

[
y = \frac{m_1y_2 + m_2y_1}{m_1 + m_2} = \frac{2(7) + 3(-3)}{2 + 3} = \frac{14 – 9}{5} = \frac{5}{5} = 1
]

P = (4, 1)


Example 4: मध्य-बिंदु ज्ञात करना

बिंदुओं A(-3, 5) और B(7, -1) के मध्य-बिंदु के निर्देशांक ज्ञात करें।

हल:

मध्य-बिंदु सूत्र:
[
M(x, y) = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
]

[
x = \frac{-3 + 7}{2} = \frac{4}{2} = 2
]
[
y = \frac{5 + (-1)}{2} = \frac{4}{2} = 2
]

M = (2, 2)


Example 5: त्रिभुज का क्षेत्रफल और संरेखता की जाँच

जाँच करें कि बिंदु A(1, 1), B(2, 3), C(3, 5) संरेख हैं या नहीं।

हल:

त्रिभुज का क्षेत्रफल ज्ञात करें:
[
\text{Area} = \frac{1}{2} \left| x_1(y_2 – y_3) + x_2(y_3 – y_1) + x_3(y_1 – y_2) \right|
]
[
= \frac{1}{2} \left| 1(3 – 5) + 2(5 – 1) + 3(1 – 3) \right|
]
[
= \frac{1}{2} \left| 1(-2) + 2(4) + 3(-2) \right|
]
[
= \frac{1}{2} \left| -2 + 8 – 6 \right| = \frac{1}{2} \left| 0 \right| = 0
]

क्षेत्रफल = 0 है, अतः तीनों बिंदु संरेख (collinear) हैं।

वैकल्पिक विधि — ढाल (Slope) से:
AB का ढाल = (3 – 1)/(2 – 1) = 2/1 = 2
BC का ढाल = (5 – 3)/(3 – 2) = 2/1 = 2
दोनों ढाल बराबर हैं → संरेख ✅


✏️ Practice Questions (5)

Q1. बिंदुओं A(2, -1) और B(-4, 7) के बीच की दूरी ज्ञात करें।

👉 उत्तर देखें

**दूरी सूत्र:**
AB = √[(-4 – 2)² + (7 – (-1))²]
AB = √[(-6)² + (8)²]
AB = √[36 + 64]
AB = √100 = **10 इकाई**


Q2. बिंदु P, बिंदुओं A(4, -3) और B(9, 7) को मिलाने वाले रेखाखंड को 3 : 2 के अनुपात में विभाजित करता है। P के निर्देशांक ज्ञात करें।

👉 उत्तर देखें

m₁ = 3, m₂ = 2
x = [3(9) + 2(4)] / (3 + 2) = (27 + 8)/5 = 35/5 = 7
y = [3(7) + 2(-3)] / (3 + 2) = (21 – 6)/5 = 15/5 = 3
**P = (7, 3)**


Q3. सिद्ध करें कि बिंदु A(2, -2), B(7, 3), C(12, 8) संरेख हैं।

👉 उत्तर देखें

त्रिभुज का क्षेत्रफल:
= ½ | 2(3 – 8) + 7(8 – (-2)) + 12((-2) – 3) |
= ½ | 2(-5) + 7(10) + 12(-5) |
= ½ | -10 + 70 – 60 |
= ½ | 0 | = 0
क्षेत्रफल = 0 → **संरेख हैं।**


Q4. बिंदुओं A(3, 2) और B(7, 6) के मध्य-बिंदु के निर्देशांक ज्ञात करें और मूल बिंदु से इसकी दूरी भी ज्ञात करें।

👉 उत्तर देखें

मध्य-बिंदु M:
x = (3 + 7)/2 = 5
y = (2 + 6)/2 = 4
M = (5, 4)

मूल बिंदु से दूरी = √(5² + 4²) = √(25 + 16) = √41 इकाई


Q5. यदि त्रिभुज ABC के शीर्ष A(1, 0), B(4, 3) और C(6, y) हैं, और त्रिभुज का क्षेत्रफल 6 वर्ग इकाई है, तो y का मान ज्ञात करें।

👉 उत्तर देखें

क्षेत्रफल = ½ | 1(3 – y) + 4(y – 0) + 6(0 – 3) |
6 = ½ | 3 – y + 4y + 6(-3) |
6 = ½ | 3 + 3y – 18 |
6 = ½ | 3y – 15 |
12 = | 3y – 15 |

3y – 15 = 12 या 3y – 15 = -12
3y = 27 या 3y = 3
y = 9 या y = 1

**y = 9** या **y = 1**


📅 Generated: 28 June 2026 | 📚 MP Board Class 10 Maths

MP Board Class 10 Science Chapter 1: Chemical Reactions & Equations Notes 2027 — Types, Balancing, Redox & PYQs

Chapter 1: Chemical Reactions & Equations is a fundamental chapter in MP Board Class 10 Science, carrying 8–10 marks in the annual board exam. This chapter introduces the concept of chemical changes, types of chemical reactions, balancing chemical equations, and oxidation-reduction processes. Questions range from 1-mark MCQs and VSA to 3-mark short answer and 5-mark long answer questions. Mastery of writing and balancing chemical equations is essential for scoring high marks in this chapter.

⚗️ Chemical Equations & Balancing

A chemical equation is a symbolic representation of a chemical reaction using chemical formulas. Reactants are written on the left side and products on the right side, separated by an arrow (→).

📝 Rules for Writing Chemical Equations

  • Write the correct chemical formulas of reactants and products
  • Use the arrow (→) to separate reactants from products
  • Indicate physical states: (s) solid, (l) liquid, (g) gas, (aq) aqueous
  • Balance the equation so that the number of atoms of each element is equal on both sides
  • Use coefficients (numbers before formulas) to balance — never change subscripts

📐 Solved Example 1: Burning of Magnesium

Unbalanced: Mg + O₂ → MgO

Step 1: Count atoms — Left: Mg=1, O=2 | Right: Mg=1, O=1

Step 2: Balance oxygen — put coefficient 2 before MgO: Mg + O₂ → 2MgO

Step 3: Balance magnesium — put coefficient 2 before Mg: 2Mg + O₂ → 2MgO

Balanced: 2Mg + O₂ → 2MgO

📐 Solved Example 2: Decomposition of Ferrous Sulphate

Unbalanced: FeSO₄ → Fe₂O₃ + SO₂ + SO₃

Step 1: Count atoms — Left: Fe=1, S=1, O=4 | Right: Fe=2, S=2, O=8

Step 2: Balance Fe — put coefficient 2 before FeSO₄: 2FeSO₄ → Fe₂O₃ + SO₂ + SO₃

Step 3: Balance S — Left S=2, Right S=2 ✓ | Balance O — Left O=8, Right O=8 ✓

Balanced: 2FeSO₄ → Fe₂O₃ + SO₂ + SO₃

📐 Solved Example 3: Reaction of Lead Nitrate with Potassium Iodide

Unbalanced: Pb(NO₃)₂ + KI → PbI₂ + KNO₃

Step 1: Count atoms — Left: Pb=1, N=2, O=6, K=1, I=1 | Right: Pb=1, I=2, K=1, N=1, O=3

Step 2: Balance I — put coefficient 2 before KI: Pb(NO₃)₂ + 2KI → PbI₂ + KNO₃

Step 3: Balance NO₃ — Left NO₃=2, put coefficient 2 before KNO₃: Pb(NO₃)₂ + 2KI → PbI₂ + 2KNO₃

Step 4: Verify — Left: Pb=1, N=2, O=6, K=2, I=2 | Right: Pb=1, I=2, K=2, N=2, O=6 ✓

Balanced: Pb(NO₃)₂ + 2KI → PbI₂ + 2KNO₃

➕ Combination Reactions

A combination reaction is a reaction in which two or more substances (elements or compounds) combine to form a single new substance. The general form is: A + B → AB.

🔥 Examples of Combination Reactions

  • Burning of coal: C + O₂ → CO₂ (Carbon + Oxygen → Carbon dioxide)
  • Formation of water: 2H₂ + O₂ → 2H₂O (Hydrogen + Oxygen → Water)
  • Formation of calcium oxide: 2Ca + O₂ → 2CaO (Calcium + Oxygen → Calcium oxide)
  • Burning of magnesium: 2Mg + O₂ → 2MgO (Magnesium + Oxygen → Magnesium oxide — bright white flame)
🎯 Exam Tip: MP Board 2027 — Combination reactions often appear as 1-mark MCQs (identify the type) or 2-mark questions asking for one example with balanced equation. Remember the magnesium burning experiment — it’s a very common question.

🧪 Decomposition Reactions

A decomposition reaction is a reaction in which a single compound breaks down into two or more simpler substances. The general form is: AB → A + B. Decomposition reactions are the opposite of combination reactions.

🔬 Types of Decomposition Reactions

Type Energy Source Example
Thermal Decomposition Heat 2FeSO₄ → Fe₂O₃ + SO₂ + SO₃ (green to brown)
Electrolytic Decomposition Electricity 2H₂O → 2H₂ + O₂ (electrolysis of water)
Photochemical Decomposition Light 2AgCl → 2Ag + Cl₂ (sunlight, used in photography)

📘 Important Experiment — Thermal Decomposition of Ferrous Sulphate

When green-coloured FeSO₄·7H₂O crystals are heated, they first lose water (turn white), then decompose to give ferric oxide (red-brown), sulphur dioxide (pungent smell), and sulphur trioxide. This is a thermal decomposition reaction.

🔄 Displacement Reactions

A displacement reaction is a reaction in which a more reactive element displaces a less reactive element from its compound. The general form is: A + BX → AX + B (where A is more reactive than B).

⚔️ Examples of Displacement Reactions

  • Iron + Copper Sulphate: Fe + CuSO₄ → FeSO₄ + Cu (Iron displaces copper — blue solution turns green)
  • Zinc + Copper Sulphate: Zn + CuSO₄ → ZnSO₄ + Cu (Zinc displaces copper — blue colour fades)
  • Lead + Copper Chloride: Pb + CuCl₂ → PbCl₂ + Cu (Lead displaces copper)

🔄 Double Displacement Reactions

A double displacement reaction is a reaction in which two compounds exchange their ions (or radicals) to form two new compounds. The general form is: AB + CD → AD + CB.

Double displacement reactions are further classified into precipitation reactions (where an insoluble solid forms) and neutralization reactions (where an acid and base react to form salt and water).

🧪 Examples of Double Displacement Reactions

  • Precipitation (Yellow Precipitate): Pb(NO₃)₂ + 2KI → PbI₂ + 2KNO₃ (Yellow precipitate of PbI₂ forms)
  • Precipitation (White Precipitate): NaCl + AgNO₃ → AgCl + NaNO₃ (White precipitate of AgCl forms)
  • Neutralization: HCl + NaOH → NaCl + H₂O (Acid + Base → Salt + Water)
🎯 Exam Tip: MP Board 2027 — Distinguishing between displacement and double displacement reactions is a frequently asked 2-mark question. Remember: displacement involves one element + one compound; double displacement involves two compounds exchanging ions.

⚡ Oxidation & Reduction

📖 Definitions

  • Oxidation: Addition of oxygen OR removal of hydrogen from a substance
  • Reduction: Addition of hydrogen OR removal of oxygen from a substance
  • Redox Reaction: A reaction where oxidation and reduction occur simultaneously
  • Oxidizing Agent: A substance that provides oxygen (or removes hydrogen) — gets reduced itself
  • Reducing Agent: A substance that provides hydrogen (or removes oxygen) — gets oxidized itself

📊 Common Examples of Redox Reactions

Reaction Substance Oxidized Substance Reduced Reducing Agent Oxidizing Agent
ZnO + C → Zn + CO C (Carbon gains O → CO) ZnO (Zinc loses O → Zn) C (Carbon) ZnO (Zinc oxide)
CuO + H₂ → Cu + H₂O H₂ (Hydrogen gains O → H₂O) CuO (Copper loses O → Cu) H₂ (Hydrogen) CuO (Copper oxide)
MnO₂ + 4HCl → MnCl₂ + 2H₂O + Cl₂ HCl (Chlorine loses H) MnO₂ (Manganese gains H) HCl MnO₂

🦀 Corrosion — A Real-World Example of Oxidation

Corrosion is the slow destruction of metals due to reaction with oxygen, moisture, and other substances in the environment. The most well-known example is rusting of iron:

4Fe + 3O₂ + 2xH₂O → 2Fe₂O₃·xH₂O (Hydrated iron oxide — rust)

  • Rusting requires both oxygen and water
  • Prevention: Painting, oiling, galvanization (coating with zinc), alloying
  • Silver tarnishes (turns black) due to reaction with H₂S in air: 4Ag + 2H₂S + O₂ → 2Ag₂S + 2H₂O

🍏 Rancidity — Oxidation of Food

Rancidity is the spoilage of food containing fats and oils due to oxidation, producing unpleasant smell and taste. Prevention methods include:

  • Adding antioxidants (e.g., BHA, BHT) to packaged foods
  • Storing food in airtight containers
  • Refrigeration to slow down oxidation
  • Packing in oxygen-free environment (nitrogen flushing)

📝 Practice Questions

  1. Q1: Balance the following chemical equation: Fe + H₂O → Fe₃O₄ + H₂. Identify the type of reaction.
  2. Q2: What happens when green ferrous sulphate crystals are heated? Write the balanced chemical equation and state the type of reaction.
  3. Q3: Distinguish between displacement and double displacement reactions with one example each.
  4. Q4: In the reaction ZnO + C → Zn + CO, identify the substance that is oxidized, reduced, the oxidizing agent, and the reducing agent.
  5. Q5: Why do we apply paint on iron articles? Explain two methods to prevent rusting.

✅ Answer Key

  • A1: 3Fe + 4H₂O → Fe₃O₄ + 4H₂. This is a displacement reaction (iron displaces hydrogen from water).
  • A2: Green FeSO₄ crystals first lose water (turn white), then decompose: 2FeSO₄ → Fe₂O₃ + SO₂ + SO₃. This is a thermal decomposition reaction.
  • A3: Displacement: Fe + CuSO₄ → FeSO₄ + Cu (one element + one compound). Double displacement: Pb(NO₃)₂ + 2KI → PbI₂ + 2KNO₃ (two compounds exchange ions).
  • A4: Oxidized: C (Carbon gains oxygen). Reduced: ZnO (Zinc oxide loses oxygen). Reducing agent: C. Oxidizing agent: ZnO.
  • A5: Paint prevents iron from coming into contact with oxygen and moisture, thus preventing rusting. Methods: (a) Galvanization — coating with zinc, (b) Oiling/greasing — creating a protective layer, (c) Alloying — making stainless steel.

📋 Previous Year Questions (2017–2026)

Year Question Marks
2026 Balance the equation: Fe₂O₃ + Al → Al₂O₃ + Fe. Name the type of reaction. (Hint: This is a thermite reaction used in welding) 3
2025 What is a redox reaction? Explain with the example of copper oxide reacting with hydrogen. 3
2024 Write the balanced chemical equation for the reaction of lead nitrate with potassium iodide. What colour precipitate is formed? Name the type of reaction. 3
2023 Define combination reaction. Give two examples with balanced equations. 3
2022 Why is respiration considered an exothermic reaction? Explain in terms of oxidation. 2
2021 What is rancidity? Write two methods to prevent it. 2
2020 Classify the following reactions into combination, decomposition, displacement, and double displacement: (i) CaO + H₂O → Ca(OH)₂ (ii) Zn + H₂SO₄ → ZnSO₄ + H₂ (iii) 2KClO₃ → 2KCl + 3O₂ (iv) BaCl₂ + Na₂SO₄ → BaSO₄ + 2NaCl 4
2019 Write the balanced equation for the reaction of iron with copper sulphate solution. What change in colour is observed? Why? 3
2018 Differentiate between oxidation and reduction. In the reaction MnO₂ + 4HCl → MnCl₂ + 2H₂O + Cl₂, identify the oxidizing and reducing agents. 3
2017 What happens when silver chloride is exposed to sunlight? Write the chemical equation and name the type of decomposition. 2

MP Board Previous Year Papers 2027 — Solved PYPs Class 10 & 12

MP Board Previous Year Papers 2027 — Class 10 & 12 All Subjects (2017-2026)

MP Board ke Previous Year Papers (PYPs) solve karna exam mein 90%+ score ka सबसे बड़ा रहस्य है. Is page par aapko milega Class 10 aur Class 12 ke saare subjects ke 10 saal ke solved papers (2017-2026) with answers.

📚 Class 10 Previous Year Papers:
Class 10 All Subjects
• Science Previous Year Papers
• Maths Previous Year Papers
• English Previous Year Papers
• Social Science Previous Year Papers
• Hindi Previous Year Papers
📚 Class 12 Previous Year Papers:
Class 12 All Subjects
• Physics Previous Year Papers
• Chemistry Previous Year Papers
• Mathematics Previous Year Papers
• Biology Previous Year Papers
• Accountancy Previous Year Papers
• Business Studies Previous Year Papers
• Economics Previous Year Papers

PYP Solve Karne ke 5 Fayde

  1. Exam pattern pata chal jata hai — kaunse chapter se kitne marks ke questions aate hain
  2. Time management seekho — actual exam mein time kaise lagana hai
  3. Repeated questions identify karo — har saal kuch questions repeat hote hain
  4. Confidence badhta hai — jaan pehchan pattern dekh kar dar kam hota hai
  5. Weak areas pata chalte hain — jahan marks nahi aa rahe wahan zyada focus karo

PYQ Practice Tips

20-Year Rule: Pichle 10 saal ke papers 2 baar solve karo — ek baar chapter ke baad, doosri baar pre-board time. MP Board mein 60% questions previous years se repeat ya similar aate hain.

Smart Study Tips 2027 — Learn Faster for MP Board Exams

Smart Study Tips for MP Board 2027 — Learn Faster, Score Better

Smart Study ka matlab nahi hai kam padhna — smart study ka matlab hai efficient padhna. Is article mein hum discuss karenge science-backed smart study techniques jo MP Board Class 10 aur Class 12 students ko 90%+ score dila sakti hain.

Smart Study Techniques Covered:
1. Pomodoro Technique — 25-5 Rule
2. Active Recall — Yaad rakhne ka scientific tarika
3. Spaced Repetition — Time table optimization
4. Feynman Technique — Kisi ko samjhao to samajh aayega
5. Mind Mapping — Visual learning
6. Interleaving — Subjects mix karo
7. Previous Year Paper Analysis — Pattern decipher

1. Pomodoro Technique

25 minutes study, 5 minutes break. Har 4 cycles ke baad 15-20 min break. Isse aapki concentration 40% improve hoti hai. MP Board students ke liye yeh sabse effective technique hai.

2. Active Recall — सबसे Powerful Method

Chapter padhne ke baad turant ushe yaad karne ki koshish karo — book dekhe bina. Research kehta hai ki Active Recall normal reading se 50% zyada effective hai.

3. Smart Study Time Table

Time Activity Subject
6-7 AM Fresh mind — toughest subject Maths/Physics
7-8 AM Mild subject Chemistry/Bio
8-8:30 AM Breakfast
8:30-10 AM Pomodoro session Mixed revision

MP Board 2027 mein smart study karo — 95%+ score possible hai!

MP Board Previous Year Papers 2027 — Solved PYPs Class 10 & 12

MP Board Previous Year Papers 2027 — Class 10 & 12 All Subjects (2017-2026)

MP Board ke Previous Year Papers (PYPs) solve karna exam mein 90%+ score ka सबसे बड़ा रहस्य है. Is page par aapko milega Class 10 aur Class 12 ke saare subjects ke 10 saal ke solved papers (2017-2026) with answers.

📚 Class 10 Previous Year Papers:
Class 10 All Subjects
• Science Previous Year Papers
• Maths Previous Year Papers
• English Previous Year Papers
• Social Science Previous Year Papers
• Hindi Previous Year Papers
📚 Class 12 Previous Year Papers:
Class 12 All Subjects
• Physics Previous Year Papers
• Chemistry Previous Year Papers
• Mathematics Previous Year Papers
• Biology Previous Year Papers
• Accountancy Previous Year Papers
• Business Studies Previous Year Papers
• Economics Previous Year Papers

PYP Solve Karne ke 5 Fayde

  1. Exam pattern pata chal jata hai — kaunse chapter se kitne marks ke questions aate hain
  2. Time management seekho — actual exam mein time kaise lagana hai
  3. Repeated questions identify karo — har saal kuch questions repeat hote hain
  4. Confidence badhta hai — jaan pehchan pattern dekh kar dar kam hota hai
  5. Weak areas pata chalte hain — jahan marks nahi aa rahe wahan zyada focus karo

PYQ Practice Tips

20-Year Rule: Pichle 10 saal ke papers 2 baar solve karo — ek baar chapter ke baad, doosri baar pre-board time. MP Board mein 60% questions previous years se repeat ya similar aate hain.

Smart Study Tips 2027 — Learn Faster for MP Board Exams

Smart Study Tips for MP Board 2027 — Learn Faster, Score Better

Smart Study ka matlab nahi hai kam padhna — smart study ka matlab hai efficient padhna. Is article mein hum discuss karenge science-backed smart study techniques jo MP Board Class 10 aur Class 12 students ko 90%+ score dila sakti hain.

Smart Study Techniques Covered:
1. Pomodoro Technique — 25-5 Rule
2. Active Recall — Yaad rakhne ka scientific tarika
3. Spaced Repetition — Time table optimization
4. Feynman Technique — Kisi ko samjhao to samajh aayega
5. Mind Mapping — Visual learning
6. Interleaving — Subjects mix karo
7. Previous Year Paper Analysis — Pattern decipher

1. Pomodoro Technique

25 minutes study, 5 minutes break. Har 4 cycles ke baad 15-20 min break. Isse aapki concentration 40% improve hoti hai. MP Board students ke liye yeh sabse effective technique hai.

2. Active Recall — सबसे Powerful Method

Chapter padhne ke baad turant ushe yaad karne ki koshish karo — book dekhe bina. Research kehta hai ki Active Recall normal reading se 50% zyada effective hai.

3. Smart Study Time Table

Time Activity Subject
6-7 AM Fresh mind — toughest subject Maths/Physics
7-8 AM Mild subject Chemistry/Bio
8-8:30 AM Breakfast
8:30-10 AM Pomodoro session Mixed revision

MP Board 2027 mein smart study karo — 95%+ score possible hai!

Class 10 Maths Chapter 6: Triangles – Notes

🔺 MP Board Class 10 Maths — Chapter 6: त्रिभुज (Triangles)


📌 Key Concepts & Formulas

1. समरूप आकृतियाँ (Similar Figures)

  • दो आकृतियाँ समरूप (similar) कहलाती हैं यदि उनका आकार समान हो लेकिन आमाप (size) भिन्न हो।
  • समरूप त्रिभुजों के लिए: संगत भुजाएँ समानुपाती (proportional) होती हैं और संगत कोण बराबर होते हैं।
गुण सर्वांगसम (Congruent) समरूप (Similar)
आकार समान समान
आमाप समान भिन्न हो सकता है
चिह्न ~

2. समरूपता के लिए मापदंड (Criteria for Similarity)

(a) AAA समरूपता (Angle-Angle-Angle) / AA कसौटी

यदि दो त्रिभुजों के दो कोण बराबर हों, तो वे समरूप होते हैं। (तीसरा कोण स्वतः बराबर हो जाता है)

यदि ∠A = ∠D और ∠B = ∠E, तो △ABC ~ △DEF

(b) SSS समरूपता (Side-Side-Side)

यदि दो त्रिभुजों की संगत भुजाएँ समानुपाती हों, तो वे समरूप होते हैं।

AB/DE = BC/EF = CA/FD → △ABC ~ △DEF

(c) SAS समरूपता (Side-Angle-Side)

यदि दो त्रिभुजों में एक कोण बराबर हो और उसे घेरने वाली भुजाएँ समानुपाती हों, तो वे समरूप होते हैं।

AB/DE = AC/DF और ∠A = ∠D → △ABC ~ △DEF


3. थेल्स प्रमेय (Thales Theorem) / Basic Proportionality Theorem (BPT)

कथन: यदि किसी त्रिभुज में एक भुजा के समांतर रेखा खींची जाए, तो वह अन्य दो भुजाओं को समान अनुपात में विभाजित करती है।

△ABC में, यदि DE ∥ BC, तो:

AD/DB = AE/EC

Converse of BPT: यदि कोई रेखा दो भुजाओं को समान अनुपात में विभाजित करे, तो वह तीसरी भुजा के समांतर होती है।


4. समरूप त्रिभुजों के क्षेत्रफल (Areas of Similar Triangles)

दो समरूप त्रिभुजों के क्षेत्रफलों का अनुपात उनकी संगत भुजाओं के वर्गों के अनुपात के बराबर होता है।

यदि △ABC ~ △DEF, तो:

ar(△ABC) / ar(△DEF) = (AB/DE)² = (BC/EF)² = (CA/FD)²


5. पाइथागोरस प्रमेय (Pythagoras Theorem)

कथन: समकोण त्रिभुज में, कर्ण का वर्ग शेष दो भुजाओं के वर्गों के योग के बराबर होता है।

△ABC में, यदि ∠B = 90°, तो:

AC² = AB² + BC²

Converse of Pythagoras: यदि किसी त्रिभुज में एक भुजा का वर्ग शेष दो भुजाओं के वर्गों के योग के बराबर हो, तो वह त्रिभुज समकोण त्रिभुज होता है।


6. महत्वपूर्ण सूत्र (सारांश)

कसौटी शर्त परिणाम
AA/AAA दो कोण बराबर △ ~ △
SSS भुजाएँ समानुपाती △ ~ △
SAS दो भुजाएँ समानुपाती, बीच का कोण बराबर △ ~ △
BPT DE ∥ BC AD/DB = AE/EC
क्षेत्रफल △ABC ~ △DEF ar(△ABC) = k² × ar(△DEF)
Pythagoras ∠B = 90° AC² = AB² + BC²

📝 Solved Examples (5)

Example 1: BPT प्रमेय लागू करना

△ABC में, DE ∥ BC है। AD = 3 सेमी, DB = 5 सेमी, AE = 6 सेमी है। EC ज्ञात करें।

हल:

BPT से: AD/DB = AE/EC
3/5 = 6/EC
3 × EC = 5 × 6
EC = 30/3
EC = 10 सेमी ✅

Example 2: समरूप त्रिभुजों की पहचान — SSS कसौटी

जाँच करें कि क्या △ABC और △DEF समरूप हैं:
AB = 6 सेमी, BC = 9 सेमी, CA = 12 सेमी
DE = 2 सेमी, EF = 3 सेमी, FD = 4 सेमी

हल:

AB/DE = 6/2 = 3
BC/EF = 9/3 = 3
CA/FD = 12/4 = 3

सभी अनुपात बराबर हैं (3:1)।
∴ SSS कसौटी से, △ABC ~ △DEF ✅

Example 3: समरूप त्रिभुजों के क्षेत्रफल

△ABC ~ △DEF है। AB = 10 सेमी, DE = 5 सेमी, और ar(△ABC) = 80 वर्ग सेमी है। ar(△DEF) ज्ञात करें।

हल:

समरूप त्रिभुजों के क्षेत्रफलों का अनुपात:
ar(△ABC) / ar(△DEF) = (AB/DE)²
80 / ar(△DEF) = (10/5)²
80 / ar(△DEF) = 4
ar(△DEF) = 80/4 = 20 वर्ग सेमी ✅

Example 4: पाइथागोरस प्रमेय

एक समकोण त्रिभुज में, कर्ण = 13 सेमी और एक भुजा = 5 सेमी है। दूसरी भुजा ज्ञात करें।

हल:

माना ∆ABC है जिसमें ∠B = 90° और कर्ण AC = 13 सेमी, AB = 5 सेमी

पाइथागोरस प्रमेय से:
AC² = AB² + BC²
13² = 5² + BC²
169 = 25 + BC²
BC² = 144
BC = √144 = 12 सेमी ✅

Example 5: पाइथागोरस प्रमेय का विलोम (Converse)

जाँच करें कि क्या 6 सेमी, 8 सेमी, 10 सेमी भुजाओं वाला त्रिभुज समकोण त्रिभुज है।

हल:

सबसे बड़ी भुजा = 10 सेमी (यह कर्ण होगा)

जाँच: (कर्ण)² = 10² = 100
अन्य दो भुजाओं के वर्गों का योग = 6² + 8² = 36 + 64 = 100

चूँकि 10² = 6² + 8², ∴ यह एक समकोण त्रिभुज है।
Converse of Pythagoras Theorem से सत्यापित ✅

✏️ Practice Questions (5)

Q1. △ABC में, DE ∥ BC है। AD = 2.4 सेमी, DB = 3.6 सेमी, EC = 4.5 सेमी है। AE ज्ञात करें।

👉 उत्तर देखें

**BPT से:** AD/DB = AE/EC
2.4/3.6 = AE/4.5
AE = (2.4 × 4.5) / 3.6
AE = 10.8 / 3.6 = **3 सेमी**


Q2. जाँच करें कि △ABC ~ △DEF है या नहीं:

AB = 8 सेमी, BC = 16 सेमी, CA = 20 सेमी
DE = 4 सेमी, EF = 8 सेमी, FD = 10 सेमी

👉 उत्तर देखें

AB/DE = 8/4 = 2
BC/EF = 16/8 = 2
CA/FD = 20/10 = 2
सभी अनुपात बराबर हैं (2:1)।
∴ SSS कसौटी से, **△ABC ~ △DEF** ✅


Q3. △ABC ~ △PQR है। AB = 6 सेमी, PQ = 9 सेमी, और ar(△ABC) = 36 वर्ग सेमी है। ar(△PQR) ज्ञात करें।

👉 उत्तर देखें

ar(△ABC) / ar(△PQR) = (AB/PQ)²
36 / ar(△PQR) = (6/9)² = (2/3)² = 4/9
ar(△PQR) = 36 × 9/4 = 324/4 = **81 वर्ग सेमी**


Q4. एक समकोण त्रिभुज में, कर्ण 17 सेमी और एक भुजा 15 सेमी है। दूसरी भुजा की लंबाई ज्ञात करें।

👉 उत्तर देखें

पाइथागोरस प्रमेय से:
17² = 15² + BC²
289 = 225 + BC²
BC² = 64
BC = √64 = **8 सेमी**


Q5. क्या 7 सेमी, 24 सेमी, 25 सेमी भुजाओं वाला त्रिभुज समकोण त्रिभुज है? कारण सहित बताएँ।

👉 उत्तर देखें

सबसे बड़ी भुजा = 25 सेमी
(कर्ण)² = 25² = 625
अन्य दो भुजाओं के वर्गों का योग = 7² + 24² = 49 + 576 = 625
चूँकि 25² = 7² + 24², **हाँ, यह समकोण त्रिभुज है** ✅


📅 Generated: 27 June 2026 | 📚 MP Board Class 10 Maths — Chapter 6: Triangles (त्रिभुज)

Class 10 Science PY Paper 2024 – Solved Questions with

Are you preparing for the MP Board Class 10 Science exam in 2027? Solving the MP Board Class 10 Science Previous Year Paper 2024 is one of the most effective ways to understand the exam pattern, mark distribution, and important topics. In this post, we provide the fully solved 2024 Science paper with detailed answers to help you score 90%+ marks in your board exams.

Table of Contents

  1. Paper Overview and Exam Pattern
  2. Section A – Objective Questions (1 Mark Each)
  3. Section B – Very Short Answer Questions (2 Marks Each)
  4. Section C – Short Answer Questions (3 Marks Each)
  5. Section D – Long Answer Questions (5 Marks Each)
  6. Download PDF and Tips

Paper Overview and Exam Pattern 2024

The MP Board Class 10 Science paper 2024 was conducted for 75 marks (theory) with an additional 25 marks for internal assessment. The paper was divided into four sections with the following distribution:

Section Question Type Marks No. of Questions Total Marks
A Objective / Multiple Choice 1 12 12
B Very Short Answer 2 6 12
C Short Answer 3 8 24
D Long Answer 5 3 15

Section A – Objective Questions (1 Mark Each)

Q1. The chemical formula of washing soda is:

(a) Na2CO3.10H2O (b) Na2CO3.7H2O (c) NaHCO3 (d) NaOH

Answer: (a) Na2CO3.10H2O

Washing soda is sodium carbonate decahydrate, used in laundry and glass manufacturing.


Q2. Which of the following is a non-biodegradable substance?

(a) Paper (b) Wood (c) Polythene bag (d) Cotton cloth

Answer: (c) Polythene bag

Non-biodegradable substances like plastics do not decompose naturally for hundreds of years.


Q3. The pH of a neutral solution at 25C is:

(a) 0 (b) 7 (c) 14 (d) 1

Answer: (b) 7

pH 7 indicates neutral – neither acidic nor basic. Pure water has pH 7 at 25C.


Q4. The SI unit of electric current is:

(a) Volt (b) Ohm (c) Ampere (d) Watt

Answer: (c) Ampere

Current is measured in amperes (A). 1 Ampere = 1 Coulomb of charge flowing per second.


Q5. The blood component that helps in clotting is:

(a) RBC (b) WBC (c) Platelets (d) Plasma

Answer: (c) Platelets

Platelets (thrombocytes) are responsible for blood clotting and preventing excessive bleeding.


Q6. The functional group present in alcohols is:

(a) -CHO (b) -COOH (c) -OH (d) -NH2

Answer: (c) -OH

The hydroxyl group (-OH) is the functional group that characterizes alcohols like ethanol (C2H5OH).

Section B – Very Short Answer Questions (2 Marks Each)

Q7. What is a double displacement reaction? Give an example.

Answer: A double displacement reaction is a reaction in which two compounds exchange their ions to form two new compounds. For example:

AgNO3(aq) + NaCl(aq) rarr; AgCl(s) + NaNO3(aq)

Here, Ag+ and Na+ exchange places to form silver chloride (white precipitate) and sodium nitrate.


Q8. Define the power of a lens. Write its SI unit.

Answer: The power of a lens is the measure of its ability to converge or diverge light rays. It is defined as the reciprocal of the focal length in metres.

Power (P) = 1/f (in metres)

SI unit of power is Dioptre (D).

A convex lens has positive power, while a concave lens has negative power.


Q9. Why is the stomach lining not damaged by hydrochloric acid?

Answer: The stomach lining is protected by a thick layer of mucus secreted by the gastric glands. This mucus forms a protective barrier between the stomach wall and the acidic gastric juice (HCl), preventing self-digestion of the stomach lining.

Section C – Short Answer Questions (3 Marks Each)

Q10. Explain the process of photosynthesis with a balanced chemical equation.

Answer: Photosynthesis is the process by which green plants convert light energy into chemical energy (food) using carbon dioxide and water in the presence of chlorophyll and sunlight.

Component Function
Chlorophyll Pigment that traps sunlight energy
Sunlight Provides energy for the reaction
Carbon dioxide + Water Raw materials
Glucose + Oxygen Products

6CO2 + 6H2O – with sunlight/chlorophyll -gt; C6H12O6 + 6O2


Q11. State Ohm’s law. Write the formula and its SI units.

Answer: Ohm’s law states that the potential difference across a conductor is directly proportional to the current flowing through it, provided the temperature and physical conditions remain constant.

V = I x R

Where:

  • V = Potential difference (Volts)
  • I = Current (Amperes)
  • R = Resistance (Ohms)

Section D – Long Answer Questions (5 Marks Each)

Q12. Explain the reactivity series of metals. How can you extract metals in the middle of the activity series?

Answer: The reactivity series (or activity series) of metals is a list of metals arranged in decreasing order of their reactivity. The most reactive metal (potassium) is at the top, while the least reactive (gold) is at the bottom.

Metal Group Reactivity Extraction Method
K, Na, Ca, Mg, Al Very High Electrolytic reduction
Zn, Fe, Sn, Pb Moderate Reduction using carbon (smelting)
Cu, Ag, Au, Pt Low Found in native state

Metals in the middle of the reactivity series (Zn, Fe, Pb) are moderately reactive. Their oxides are reduced by heating with carbon (smelting). For example:

ZnO + C rarr; Zn + CO


Q13. Describe the process of reproduction in human beings. Explain the role of hormones in the menstrual cycle.

Answer: Human reproduction involves the following steps:

  1. Gamete Formation: Sperm in males (testes) and eggs in females (ovaries)
  2. Fertilization: Fusion of sperm and egg in the fallopian tube
  3. Implantation: The zygote divides and implants in the uterus wall
  4. Gestation: Development of the embryo for 9 months
  5. Parturition: Birth of the baby

Hormonal Control of Menstrual Cycle:

  • FSH – Stimulates egg growth in ovary
  • Estrogen – Builds the uterine lining
  • LH – Triggers ovulation (day 14)
  • Progesterone – Maintains uterine lining for implantation

Download PDF and Preparation Tips

To score above 90% in MP Board Class 10 Science 2027, follow these tips:

  • Practice with PY Papers: Solve at least the last 5 years papers (2022-2026)
  • Focus on NCERT: 90% of questions come directly from NCERT textbooks
  • Master Diagrams: Practice drawing human heart, eye, neuron, and plant cell
  • Numerical Practice: Focus on Ohm’s law, power, and lens formula problems
  • Chemical Equations: Learn balancing equations and important reactions
Explore More MP Board Study Materials -gt;

Key Takeaways

  • The 2024 paper was balanced across all four sections
  • Chemistry (30%), Physics (35%), and Biology (35%) had equal weightage
  • NCERT-based questions comprised around 85% of the total paper
  • Numerical and diagram-based questions are scoring if practiced well