MP Board 10 Science Ch4: Carbon Compounds Imp Qs 2027

📑 Table of Contents

1. 🎯 1. Multiple Choice Questions (1 Mark)
2. 📝 2. IUPAC Naming Questions (2 Marks)
3. 🧪 3. Chemical Reactions & Equations (3 Marks)
4. 📋 4. Long Answer Questions (5 Marks)
5. 📅 5. Previous Year Questions (2022–2025)
6. 💡 6. Expert Exam Tips
7. ❓ 7. Frequently Asked Questions

💡 MP Board Tip: In 2027 exam, MCQs from Carbon focus on IUPAC names, functional groups, and the difference between saturated and unsaturated hydrocarbons.

Q1. Write the IUPAC name of CH₃CH₂CH₂CH₃. Which homologous series does it belong to?

Solution: IUPAC name: Butane. It belongs to the alkane homologous series (general formula C_nH_2n+2).

Q2. Give the IUPAC name of CH₃CH₂OH. Write its functional group.

Solution: IUPAC name: Ethanol. Functional group: Alcohol (-OH).

Q3. Write the structure of propanoic acid. What is its functional group?

Solution: Structure: CH₃CH₂COOH. Functional group: Carboxyl group (-COOH).

Q1. Write the chemical equation for combustion of ethanol. What observations confirm complete combustion?

Solution: C₂H₅OH + 3O₂ → 2CO₂ + 3H₂O + Heat + Light. Complete combustion produces a blue flame, CO₂ turns limewater milky, and water droplets appear on a cold surface.

Q2. Explain the formation of ester. Write the reaction between ethanoic acid and ethanol.

Solution: CH₃COOH + C₂H₅OH ⇌ CH₃COOC₂H₅ + H₂O (Ethyl ethanoate + water). This is an esterification reaction, done in presence of concentrated H₂SO₄. Esters have a sweet fruity smell.

Q3. What happens when ethanoic acid reacts with sodium carbonate? Write equation.

Solution: 2CH₃COOH + Na₂CO₃ → 2CH₃COONa + H₂O + CO₂. Carbon dioxide gas is produced, which turns limewater milky. This reaction is used to test for carboxylic acids.

Q1. Explain the concept of homologous series with examples. Write the first four members of alkane series with their formulas and IUPAC names.

Solution: A homologous series is a group of organic compounds with the same functional group where each successive member differs by -CH₂ group. Alkanes (C_nH_2n+2): Methane (CH₄), Ethane (C₂H₆), Propane (C₃H₈), Butane (C₄H₁₀). Properties: same chemical properties but gradual change in physical properties like boiling point and melting point.

Q2. Differentiate between saturated and unsaturated hydrocarbons. Explain the test to distinguish them.

Solution: Saturated hydrocarbons have single bonds (C-C) — alkanes with formula C_nH_2n+2. Unsaturated hydrocarbons have double/triple bonds — alkenes (C_nH_2n) and alkynes (C_nH_2n-2). Test: Add bromine water (red-brown). Saturated: no change. Unsaturated: bromine water decolourises, showing addition reaction.

📌 Key to Scoring Full Marks: In the 2027 exam, always show the structural formula before writing IUPAC names. For reaction-based questions, write balanced equations with correct molecular formulas. Draw soap/micelle diagrams neatly for saponification questions.

Q1: How many marks does Carbon chapter carry in MP Board Class 10 Science?

The Carbon and its Compounds chapter typically carries 10–14 marks in the MP Board exam — 2-3 MCQs (1 mark each), one IUPAC naming question (2 marks), one reaction-based question (3 marks), and one long answer (5 marks).

Q2: What is the most important topic for 2027?

IUPAC nomenclature, esterification and saponification reactions, properties of ethanol and ethanoic acid, and the homologous series concept are the highest priority topics.

Q3: What is the difference between ethanol and ethanoic acid?

Ethanol (C₂H₅OH) is an alcohol with -OH group, used in alcoholic drinks and as solvent. Ethanoic acid (CH₃COOH) is a carboxylic acid with -COOH group, used as vinegar. Ethanoic acid turns blue litmus red, while ethanol does not.

Q4: Why does carbon form covalent bonds?

Carbon has 4 valence electrons and requires 4 more to complete its octet. Instead of gaining or losing 4 electrons (which would require high energy), carbon shares electrons to form covalent bonds — this is more energy-efficient.

Q5: What is saponification? Write its equation and uses.

Saponification is the alkaline hydrolysis of ester to form soap and glycerol. Equation: Ester + NaOH → Sodium salt of carboxylic acid (soap) + Alcohol. Uses: Manufacturing of soap, medicines, and cosmetics.