Class 12 Physics Chapter 1 Electric Charges and Fields

Chapter 1: Electric Charges and Fields is a foundational chapter in MP Board Class 12 Physics, carrying significant weight (5–7 marks) in the annual board exam. This chapter introduces the concept of electric charge, Coulomb’s law, electric fields, electric flux, Gauss’s law and its applications. Questions range from 1-mark MCQs and VSA to 5-mark derivations and numerical problems. A strong grasp of vector mathematics and superposition principle is essential for mastering this chapter.

⚡ Electric Charge — Types & Properties

Electric charge is the fundamental property of matter responsible for all electromagnetic interactions. Charges are of two types: positive (proton-like, deficiency of electrons) and negative (electron-like, excess of electrons). Like charges repel, unlike charges attract.

🔑 Key Properties of Charge

Property Explanation Importance in Exam
Quantisation Charge exists in discrete packets: q = ±ne, where e = 1.6×10⁻¹⁹ C 📝 1-mark VSA question (direct application)
Conservation Total charge of an isolated system remains constant 📝 Conceptual 1-mark question
Additivity Net charge = scalar sum of individual charges (with signs) 📝 Numerical 2-mark problem
Invariance Charge is independent of velocity (unlike mass in relativity) 📝 1-mark conceptual (rare)
🎯 Exam Tip: For quantisation problems, remember the smallest possible charge is ±e (±1.6×10⁻¹⁹ C). If a charge value is not a multiple of e, it is NOT physically possible!

🧪 Charging Methods

  • Charging by Friction — Transfer of electrons between two objects rubbed together (glass rod + silk → glass positive, silk negative)
  • Charging by Conduction — Direct contact transfers charge from charged to uncharged body (both acquire same sign charge)
  • Charging by Induction — Redistribution of charge without direct contact; the uncharged body gets opposite sign charge

📘 Key Formula — Quantisation of Charge

q = ±ne    where n = integer (1, 2, 3, …) and e = 1.602 × 10⁻¹⁹ C

SI unit of charge: Coulomb (C). 1 C = 6.25 × 10¹⁸ electrons

⚡ Coulomb’s Law — Force Between Charges

Coulomb’s law states that the electrostatic force between two point charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them. The force acts along the line joining the two charges.

📐 Coulomb’s Law — Formula

F = k |q₁q₂| / r²

where k = 1/(4πε₀) = 9 × 10⁹ N·m²/C², ε₀ = 8.854 × 10⁻¹² C²/N·m²

Vector form: F₁₂ = k q₁q₂/r² · r̂₁₂ (force on q₁ due to q₂)

📐 Principle of Superposition

When multiple charges are present, the net force on any one charge is the vector sum of all forces exerted on it by all other individual charges. This principle is fundamental for solving numerical problems involving three or more charges.

Charge Configuration Force Calculation Marks in Exam
Two charges in vacuum F = kq₁q₂/r² (direct) 📊 2 marks
Three charges (equilateral triangle) Vector addition — parallelogram law 📊 3 marks
Charges in medium (dielectric) F_medium = F_vacuum / K (K = dielectric constant, εᵣ) 📊 2 marks
🎯 Exam Tip: In superposition problems, always DRAW a vector diagram first. Break forces into x and y components, sum them independently, then find the resultant magnitude and direction. This is the most common mistake area!

⚡ Electric Field & Field Lines

The electric field at a point is defined as the force experienced by a unit positive test charge placed at that point. Electric field lines are imaginary lines that represent the direction of the electric field in space.

📐 Electric Field Formulas

Configuration Electric Field Formula Direction
Point charge E = kq/r² Radially outward (q>0), inward (q<0)
Multiple point charges E = Σ kqᵢ/rᵢ² · r̂ᵢ Vector sum of individual fields
Infinite line charge E = λ/(2πε₀r) Perpendicular to line

📊 Properties of Electric Field Lines

  • Field lines start from positive charges and end at negative charges
  • Field lines never cross each other (unique field direction at every point)
  • The tangent at any point gives the direction of electric field at that point
  • Closer field lines indicate stronger electric field (density = field strength)
  • Field lines are perpendicular to the surface of a conductor
  • Inside a conductor in electrostatic equilibrium, electric field = 0

⚡ Electric Dipole

An electric dipole consists of two equal and opposite point charges (+q and -q) separated by a small distance 2a. The dipole moment p = q × 2a is a vector quantity directed from -q to +q. This is a highly exam-relevant topic with 3–5 mark questions.

📐 Dipole Key Formulas

Dipole moment: p = q × 2a (direction: -q → +q)

Field on axial line: E_axial = 2kp / r³ (for r >> a)

Field on equatorial line: E_eq = -kp / r³ (for r >> a)

Torque in uniform field: τ = p × E

Potential energy: U = -p·E = -pE cos θ

Property Axial Line Equatorial Line
E-field direction Parallel to p Anti-parallel to p
Field magnitude E = 2kp/r³ E = kp/r³
Ratio E_axial = 2 × E_equatorial E_eq = ½ × E_axial
🎯 Exam Tip: The derivation of E-field at axial and equatorial points of a dipole is a common 5-mark question in MP Board exams. Memorise the final formulas and the direction relationships. Also practice finding net torque when dipole is at an angle θ to uniform E.

⚡ Gauss’s Law & Applications

Electric flux (Φ) through a surface is the dot product of electric field and area vector: Φ = ∮ E·dA. The SI unit of electric flux is N·m²/C. Gauss’s law states that the total electric flux through any closed surface is equal to the net charge enclosed divided by ε₀.

📐 Gauss’s Law — Formula

Φ = ∮ E·dA = q_enclosed / ε₀

This law is valid for any closed surface (Gaussian surface) enclosing any charge distribution.

📊 Applications of Gauss’s Law (High Exam Weightage)

Charge Distribution Electric Field (E) Exam Marks
Infinite line charge (λ C/m) E = λ/(2πε₀r) 📊 3 marks
Infinite plane sheet (σ C/m²) E = σ/(2ε₀) 📊 3 marks
Spherical shell (charged conducting) Inside: E=0; Outside: E = Q/(4πε₀r²) 📊 5 marks
Uniformly charged sphere (solid) Inside: E = Qr/(4πε₀R³); Outside: E = Q/(4πε₀r²) 📊 5 marks
🎯 Exam Tip: Gauss’s law applications — especially field due to infinite sheet and spherical shell — are the MOST frequently asked derivations from this chapter (seen in 2022, 2023, 2024, 2025 papers). Learn the step-by-step Gaussian surface selection process. For infinite sheet, remember E is independent of distance r!

📝 Frequently Asked Questions

Q1: State Coulomb’s law in vector form. (MP Board 2022, 3 marks)

Answer: F₁₂ = k q₁q₂/r² · r̂₁₂ where F₁₂ is the force on q₁ due to q₂, and r̂₁₂ is the unit vector from q₂ to q₁. The vector form specifies both magnitude and direction — repulsive for like charges (positive product) and attractive for unlike charges (negative product).

Q2: Define electric dipole moment. Derive expression for electric field on axial line. (MP Board 2023, 5 marks)

Answer: Electric dipole moment p = q × 2a, where 2a is separation between charges, directed from -q to +q. On the axial line, field due to +q and -q are in opposite directions. Using superposition: E = kq/(r-a)² – kq/(r+a)². For r >> a, E_axial = 2kp/r³.

Q3: State and explain Gauss’s theorem in electrostatics. (MP Board 2024, 3 marks)

Answer: Gauss’s theorem: The total electric flux through any closed surface is equal to 1/ε₀ times the net charge enclosed by the surface. Φ = ∮ E·dA = q/ε₀. It is applicable to any closed surface (Gaussian surface) and is particularly useful for calculating electric fields of symmetric charge distributions.

Q4: What is the electric field inside a charged conducting spherical shell? (MP Board 2023, 1 mark)

Answer: Inside a charged conducting spherical shell, the electric field is zero (E = 0). This is because all excess charge resides on the outer surface, and by Gauss’s law, flux through any Gaussian surface inside the shell is zero.

Q5: Derive the expression for torque on an electric dipole in a uniform electric field. (MP Board 2022, 3 marks)

Answer: Torque τ = force × perpendicular distance = qE × (2a sin θ) = (q × 2a) × E sin θ = pE sin θ. Hence τ = p × E. Direction is given by right-hand rule. Torque is maximum when θ = 90° (τ_max = pE) and zero when θ = 0° (stable equilibrium) or θ = 180° (unstable equilibrium).

— Best of luck for your MP Board 2027 exams! 📚 —